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3 years ago

Helpppp hate factorisation

Mathematics

2 answers:

bazaltina [42]3 years ago

7 0

The answer is (x-42)×(x+42)

goldenfox [79]3 years ago

4 0

A. (x - 42)(x - 42)

b. (58-42)(58+42)= (16)(100)= 1,600

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The temperature went from -12°F to 18°F. How much did the temperature change

vlada-n [284]

Answer:

18 - (-12)

Step-by-step explanation:

Final temp. - Initial temp. = the change in temperature

By -12, we're indicating that is below zero (which is obvious) meaning that it is not in the "normal" scale nor in the imaginary scale of numbers. So, we can operate the following...

18 - (-12) = 30

So the temperature changed by 30 values or the temperature increased by 30 values, because the number is positive.

6 0

2 years ago

Please help! I will give 50 points and brainliest.

QveST [7]

Answer:

Step-by-step explanation:

f * g = (x^2 + 3x - 4) (x+4)

open bracket

x((x^2 + 3x - 4) + 4 (x^2 + 3x - 4)

x³ +3x²-4x+x²+12x-16

x³+3x²+x²-4x+12x-16

x³+4x²+8x-16 (domain is all real numbers.

f/g = (x^2 + 3x - 4)/(x+4)

factorising (x^2 + 3x - 4)

x²+4x-x_4

x(x+4) -1 (x+4)

(x+4)(x-1)

f/g = (x^2 + 3x - 4)/(x+4) =(x+4)(x-1)/(x+4) = (x-1)

Before factorisation, this was a rational function so the domain is all real numbers excluding any value that would make the denominator equal zero.

Hence I got x - 1, and x cannot equal -4

So the domain is just all real numbers without -4

8 0

2 years ago

John has a rectangular-shaped field whose length is 62.5 yards and width is 45.3 yards. The area of the field is ________ square

oee [108]

Area = 2831.25 square yards

Perimeter =215.6 yards

EXPLANATION

The area and perimeter of a rectangular field are found using the formula for finding the area and perimeter of a rectangle respectively.

That means, area of the rectangular field is given by the formula,

$A= l\times w$

We just have to substitute
$l=62.5$ and $w= 45.3$ into the given formula and evaluate.

This implies that;

$A= 62.5\times 45.3$

This gives the area of the rectangular-shaped field to be;

$A= 2831.25$ square yards.

Now for the perimeter, we use the formula

$P=2w +2l$

Or

$P=2(w +l)$

Substituting the values for the length and width gives,

$P=2(62.5+45.3)$

$\Rightarrow P=2(107.8)$

$\Rightarrow P=215.6$

Hence the perimeter of the rectangular shaped field is 215.6 yards.

8 0

3 years ago

The length of a rectangle is 10 meters more than the width. If 3 meters is added to both the length and the width, the new area

Finger [1]

Answer:

L = 20

W = 10

Step-by-step explanation:

L = (w + 10)

NL = (w + 13)

Divide 299 by 13:

299 ÷ 13 = 23

So, 23 x 13 = 299

L = 23

W = 13

Subtract 3 from both to get the original length and width

4 0

3 years ago

The cosine of the complimentary angle to 58 degrees

lana [24]

Yes
Divide it by sixty and multiply
I hope this helps

5 0

2 years ago