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sashaice [31]
3 years ago
14

Ralf spends 15 1/3 hours per month playing tennis. How many hours does he play tennis in a year?

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
3 0
15 1/3 * 12=184 because 15 *12 *1/3

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A phone company offers two monthly plans. Plan A costs $25 plus an additional $0.09 for each minute of calls. Plan B has no init
Lisa [10]

Using linear functions, it is found that the two plans cost the same for 5000 minutes of calling.

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

  • m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
  • b is the y-intercept, which is the value of y when x = 0.

For Plan A, the cost is of $25 plus an additional $0.09 for each minute of calls, hence the y-intercept is b = 25, the slope is of a = 0.09, and the function is:

A(x) = 0.09x + 25

For Plan B, the cost is of $0.14 for each minute of calls, hence the y-intercept is b = 0, the slope is of a = 0.14, and the function is:

B(x) = 0.14x

The plans cost the same for x minutes of calling, considering that:

B(x) = A(x)

0.14x = 0.09x + 25

0.05x = 250

x = \frac{250}{0.05}

x = 5000

The two plans cost the same for 5000 minutes of calling.

To learn more about linear functions, you can take a look at brainly.com/question/24808124

6 0
3 years ago
Help please need it fast
inysia [295]
I’m pretty sure the correct answer is B
5 0
3 years ago
Help please show work
BARSIC [14]

Answer:

ok first you do the small one. 13 * 5 * 1/2 =  32.5 then you do 35 *1/2=17.5. you then divide  32.5/17.5=1.86

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Revenue from Monorail Service, Las Vegas In 2005 the Las Vegas monorail charged $3 per ride and had an average ridership of abou
Karolina [17]

Answer:

A)The required linear demand equation ( q ) = -4500p + 41500

B) $4.61

   $95680.55

C) No it would not have been possible by charging a suitable price

Step-by-step explanation:

<u>A)  find the linear demand equation</u>

given two points ; ( 3, 28000 ) and ( 5, 19000 )

slope ( m ) = ( y2 - y1 ) / ( x2 - x1 )

                 = ( 19000 - 28000 ) / ( 5 - 3 )  = -4500

slope intercept is represented as ; y = mx + b

where y( 28000) = -4500(3) + b

  hence b = 41500  

hence ; y = -4500x + 41500

The required linear demand equation ( q ) = -4500p + 41500   ----- ( 1 )

p = price per ride

<u>B ) Determine the price the company should charge to maximize revenue from ridership  and corresponding daily revenue</u>

Total revenue ( R ) = qp

                               = p ( -4500p + 41500 )

  hence R = -4500p^2 + 41500p  ------ ( 2 )

To determine the price that should maximize revenue from ridership we will equate R = -4500p^2 + 41500p  to a quadratic equation R(p) = ap^2 + bp + c

where a = -4500 ,  b = 41500 , c = 0

hence p = -\frac{b}{2a}  = - \frac{41500}{2(-4500)} =  4.61

$4.61 is the price the company should charge to maximize revenue from ridership

corresponding daily revenue = R = -4500p^2 + 41500 p

where p = $4.61

hence R = -4500(4.61 )^2 + 41500(4.61) = $95680.55

C) No it would not have been possible by charging a suitable price

5 0
3 years ago
What is 0.3% of 200<br>​
allsm [11]
It’s 60 because you multiple .3 by 200
7 0
2 years ago
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