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kati45 [8]
2 years ago
7

How many cubic feet are equivalent to 1 cubic yard?explain?

Mathematics
1 answer:
motikmotik2 years ago
8 0
(1 yard )3<span> = 1</span>3<span> yard*yard*yard</span><span> = 1 yard*yard*yard</span><span> = 1 cubic yard . Since 1 yard = </span>3 feet, we have.
1 cubic yard = (1 yard)3<span> = (</span>3 feet)3<span> = </span><span>33 feet*feet*feet</span><span> = </span>27 cubic feet<span>.</span>
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Find f(-3) PLEASE HELP
Artemon [7]

Answer:

2

Step-by-step explanation:

When the point on the x-axis is on -3, the point on the y-axis is 2. Therefore, f(-3) is equal to 2.

If this helps please mark as brainliest

6 0
3 years ago
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Calculate the pH of a buffer solution made by mixing 300 mL of 0.2 M acetic acid, CH3COOH, and 200 mL of 0.3 M of its salt sodiu
Lesechka [4]

Answer:

Approximately 4.75.

Step-by-step explanation:

Remark: this approach make use of the fact that in the original solution, the concentration of  \rm CH_3COOH and \rm CH_3COO^{-} are equal.

{\rm CH_3COOH} \rightleftharpoons {\rm CH_3COO^{-}} + {\rm H^{+}}

Since \rm CH_3COONa is a salt soluble in water. Once in water, it would readily ionize to give \rm CH_3COO^{-} and \rm Na^{+} ions.

Assume that the \rm CH_3COOH and \rm CH_3COO^{-} ions in this solution did not disintegrate at all. The solution would contain:

0.3\; \rm L \times 0.2\; \rm mol \cdot L^{-1} = 0.06\; \rm mol of \rm CH_3COOH, and

0.06\; \rm mol of \rm CH_3COO^{-} from 0.2\; \rm L \times 0.3\; \rm mol \cdot L^{-1} = 0.06\; \rm mol of \rm CH_3COONa.

Accordingly, the concentration of \rm CH_3COOH and \rm CH_3COO^{-} would be:

\begin{aligned} & c({\rm CH_3COOH}) \\ &= \frac{n({\rm CH_3COOH})}{V} \\ &= \frac{0.06\; \rm mol}{0.5\; \rm L} = 0.12\; \rm mol \cdot L^{-1} \end{aligned}.

\begin{aligned} & c({\rm CH_3COO^{-}}) \\ &= \frac{n({\rm CH_3COO^{-}})}{V} \\ &= \frac{0.06\; \rm mol}{0.5\; \rm L} = 0.12\; \rm mol \cdot L^{-1} \end{aligned}.

In other words, in this buffer solution, the initial concentration of the weak acid \rm CH_3COOH is the same as that of its conjugate base, \rm CH_3COO^{-}.

Hence, once in equilibrium, the \rm pH of this buffer solution would be the same as the {\rm pK}_{a} of \rm CH_3COOH.

Calculate the {\rm pK}_{a} of \rm CH_3COOH from its {\rm K}_{a}:

\begin{aligned} & {\rm pH}(\text{solution}) \\ &= {\rm pK}_{a} \\ &= -\log_{10}({\rm K}_{a}) \\ &= -\log_{10} (1.76 \times 10^{-5}) \\ &\approx 4.75\end{aligned}.

7 0
2 years ago
Suppose you have $100 in a savings account earning 2 percent interest a year. After five years, would you have more than $102, e
pentagon [3]
You would have more than $102.

Earning 2% a year in interest would get you $2 in interest the very first year:

100(0.02) = 2

Adding this to the amount in the account, you would have 100+2 = 102 after the first year.
6 0
3 years ago
Given right triangle ABC, what is the value of tan(A)?
Blababa [14]

Answer:

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Step-by-step explanation:

Tan θ = opposite ÷ adjacent

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There are 125 calories in a candy bar. There are 12 candy bars in a box. How many calories are in each box of candy bars?
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Answer:

1500

Step-by-step explanation:

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