Answer:
The last one
Step-by-step explanation:
Actually I think it's a correct answer .
Answer:
Step-by-step explanation:
(x) = (1100 + x) (100 - .05(x-1100))
This is a quadratic, graphs as a parabola that opens downward. A maximum cam be found.
The zeros of the function are
(1100 + x) = 0 ..... or ..... [100 - .05(x-1100)] = 0
x = -1100 is the left x-intercept.
[100 - .05(x-1100)] = 0
100 = .05(x-1100)
2000 = x - 1100
x = 3100 is the right intercept.
Maximization of profits is at the mid point of the zeros (x-intercepts)
(3100 + -1100)/2 = 1000
1100 + 1000 = 2100 trees should be planted to maximize profits.
f(x) = (1100 + 1000) (100 - .05(1000-1100))
f(x) = (2000) (105) = 220,500 is the maximum profit.
I hope this helps!
The answer is D plane Qpr
