What is a point-slope equation of the line with slope –10 that goes through the point (1, 4) ?

Solve the proportion 16/50 = x/156.25

yuradex [85]

The answer for this proportion is 50.
156.25 times 16 =2,500
2,500 divided by 50=50
X=50

4 0

3 years ago

Read 2 more answers

PLEASEE HELP ME

allsm [11]

A. It says “If Nancy is having a birthday then joe will buy her a card” it could Also be C. But it says “if joe buys Nancy a card he will GIVE IT TO HER” not just buying it so the most likely answer is A

4 0

2 years ago

GIVE EXAMPLE OF ACTION PLAN THAT SHOWS A CONTEXTUALIZED LEARNING PROGRAM

dimaraw [331]

An example of contextualization in teaching is when writing skills are taught with reference to topics.

<h3>How to illustrate the information?</h3>

It should be noted that the contextualization of basic skills is the instructional approach that gives connections in teaching.

In this case, an example of contextualization in teaching is when writing skills are taught with reference to topics.

Learn more about learning on:

brainly.com/question/26711803

#SPJ1

3 0

2 years ago

Determine the length of side CB. A) 5 B) 5V 5V D) 10

ra1l [238]

Answer: $5\sqrt{3}$ which is choice C

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Explanation:

This is a 30-60-90 triangle. The short leg is 5, as it's opposite the smallest angle. The long leg is $\sqrt{3}$ times that of the short leg.

7 0

3 years ago

Five men and 5 women are ranked according to their scores on an examination. Assume that no two scores are alike and all possibl

serg [7]

Answer:

P(X=i) where i = 1,2,3,4,5,6,7,8,9,10 = 1/2, 5/18, 5/36, 5/84, 5/252, 1/252, 0, 0, 0, 0.

Step-by-step explanation:

X denotes the highest ranking achieved by the woman.

When X=1, the top ranked person is a female.

When X=2, the first person is a male and the second ranked person is a female.

Similarly, when X=3, the first two ranked persons are male and the third one is a female.

When X=4, the first three persons are male and the fourth one is a female.

When X=5, the first four persons are males and the fifth person is a female.

When X=6, the first five people are males and the sixth person is a female. The rest of the four people are also females since there are only five men in a sample space.

The probability for X=7, 8, 9, 10 is zero because there are only five men who can achieve the first five positions and the last highest rank that can be achieved by a woman is 6.

To compute the probabilities, we will use the formula:

No. of ways a female can be ranked X/Total number of ways to rank 10 people

Note that the total number of ways of ranking 10 different people is 10P10 or 10!

For X=1, the first position can be taken by any of the 5 women. The possible ways of the first person being a woman is 5C1. The rest of the 9 people can take any of the ranks. They can be ordered in 9P9 ways.

So, P(X=1) = (5C1)(9P9)/(10P10) = (5 x 362880)/(3628800) = 1/2

For X=2, the first rank must be taken by a male. The number of ways to arrange the first person as a male out of the 5 men can be calculated by 5P1. The second position must be taken by a female and rest of the 8 positions can be taken by any of the 8 people in 8P8 ways.

So, P(X=2) = (5P1)(5C1)(8P8)/(10P10) = (5 x 5 x 40320)/(3628800) = 5/18

For X=3, first two people must be men and the number of ways to arrange 2 out of 5 males at the first two positions is 5P2. The third position is a female. The rest of the 7 people can be ordered in 7P7 ways.

P(X=3) = (5P2)(5C1)(7P7)/(10P10) = (20 x 5 x 5040)/(3628800) = 5/36

P(X=4) = (5P3)(5C1)(6P6)/(10P10) = (60 x 5 x 720)/(3628800) = 5/84

P(X=5) = (5P4)(5C1)(5P5)/(10P10) = (120 x 5 x 120)/(3628800) = 5/252

P(X=6) = (5P5)(5C1)(4P4)/(10P10) = (120 x 5 x 24)/(3628800) = 1/252

P(X=7) = 0

P(X=8) = 0

P(X=9) = 0

P(X=10) = 0

7 0

3 years ago