Answer:
1+1=3, See explenation
Step-by-step explanation:
1+1=2 but thats basically 2.1 because whole numbers are boring, but 2.1 is basically 2.2 because we want it as an even number, but 2.2 is basically 2.3 because 2.3 is the luckiest number, which is basically 2.5 if you think about it because 2.3 looks like 2/3 and two thirds can't be a whole (which is why we say 3/3 instead of 2/3) and 2.5 rounded up is 3. So thats how 1+1=3
Six is the domain, while 1 is the codomain.
Answer:
See below.
Step-by-step explanation:
1.
Statement 8. triangle SQR is congruent to triangle TQP
Reason 8. ASA
2.
The only way to prove those two sides are congruent is to first prove that the triangles that contain those sides are congruent. Then you can use CPCTC to prove those sides congruent.
well, let's first off, expand the expression, 3x(x-4) => 3x²-12x, which we can also write as
f(x) = 3x² - 12x + 0
now, this is a quadratic equation with a leading term with a positive coefficient, namely its graph is a parabola, or a Cup-Shaped figure, so the graph comes from the top, goes down down down, reaches a U-turn, then goes back up up up.
the U-turn, or vertex of the quadratic, is the lowest point in the "cup".
Answer:
![\log_5{\dfrac{x^5}{\sqrt[4]{8-x}}}](https://tex.z-dn.net/?f=%5Clog_5%7B%5Cdfrac%7Bx%5E5%7D%7B%5Csqrt%5B4%5D%7B8-x%7D%7D%7D)
Step-by-step explanation:
Make use of the rules of logarithms:
log(a/b) = log(a) - log(b)
log(a^b) = b·log(a)
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![5\log_5{x}-\dfrac{1}{4}\log_5{(8-x)}=\log_5{x^5}-\log_5{\sqrt[4]{8-x}}=\log_5{\dfrac{x^5}{\sqrt[4]{8-x}}}](https://tex.z-dn.net/?f=5%5Clog_5%7Bx%7D-%5Cdfrac%7B1%7D%7B4%7D%5Clog_5%7B%288-x%29%7D%3D%5Clog_5%7Bx%5E5%7D-%5Clog_5%7B%5Csqrt%5B4%5D%7B8-x%7D%7D%3D%5Clog_5%7B%5Cdfrac%7Bx%5E5%7D%7B%5Csqrt%5B4%5D%7B8-x%7D%7D%7D)
