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4 years ago

5

How do i put 10-5y=3x in y=mx+b form

2 answers:

Novosadov [1.4K]4 years ago

6 0

Answer:

Step-by-step explanation:

put 10-5y=3x in y=mx+b form

10-5y=3x

Collecting like terms

-5y = 3x -10

Dividing by -5

y = -3/5x + 10/5

y = -3/5x + 2

Comparing to y=mx+b

m = -3/5 and b = 2

irina1246 [14]4 years ago

4 0

Step 1: Rewrite equation

10-5y=3x

Step 2: To get y alone on the left side, subtract 10 on both sides

10-5y=3x
-10 -10
__________
-5y=3x-10

Step 3: divide -5 on both sides, again to get y alone

-5y=3x-10
/-5 /-5 /-5
________
y=-3/5x+2

Final equation: y=-3/5x+2

Hope this helps :)

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Answer:

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Step-by-step explanation:

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The ratio 5 : 4 can also be written as the fraction 5/4.

The ratio pop songs, 40 : rock songs, r can be written as the fraction 40/r

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Cross Multiply:

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r = 32

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AlladinOne [14]

Answer:

Part 1)

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Part 2)

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Step-by-step explanation:

1)

We are given:

$f(x)=5x+1\text{ and } g(x)=x^2-9$

And that:

$h(x)=f(x)/g(x)$

And we want to now for which values of x is h(x) undefined.

So, by substitution:

$\displaystyle h(x)=\frac{5x+1}{x^2-9}$

Remember that for rational functions, the function will be undefined if and only if the denominator is 0.

This is because we cannot divide by 0.

So, to find the values for which the denominator is 0, set the denominator to 0 and solve for x. Therefore:

$x^2-9=0$

Add 9 to both sides:

$x^2=9$

Take the square root of both sides. Since we are taking an even-root, we will need plus/minus. Therefore:

$x=\pm 3$

So, h(x) is undefined for ±3.

Our answer is A.

2)

We are given:

$f(x)=3^x\text{ and } g(x)=3^{2x}-3^x$

And we want to find:

$h(x)\text{ if } h(x)=f(x)-g(x)$

So:

$h(x)=3^x-(3^{2x}-3^x)$

Distribute:

$h(x)=3^x-3^{2x}+3^x$

Combine like terms:

$h(x)=2(3^x)-3^{2x}$

Rewrite:

$h(x)=2(3^x)-(3^x)(3^x)$

Factor out:

$h(x)=3^x(2-3^x)$

So, our answer is C.

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3 years ago