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olasank [31]
3 years ago
5

How do i put 10-5y=3x in y=mx+b form​

Mathematics
2 answers:
Novosadov [1.4K]3 years ago
6 0

Answer:

Step-by-step explanation:

put 10-5y=3x in y=mx+b form​

10-5y=3x

Collecting like terms

-5y = 3x -10

Dividing by -5

y = -3/5x + 10/5

y = -3/5x + 2

Comparing to y=mx+b

m = -3/5 and b = 2

irina1246 [14]3 years ago
4 0
Step 1: Rewrite equation

10-5y=3x

Step 2: To get y alone on the left side, subtract 10 on both sides

10-5y=3x
-10 -10
__________
-5y=3x-10

Step 3: divide -5 on both sides, again to get y alone

-5y=3x-10
/-5 /-5 /-5
________
y=-3/5x+2


Final equation: y=-3/5x+2

Hope this helps :)
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4 0
3 years ago
Directed line segment has endpoints P(– 8, – 4) and Q(4, 12). Determine the point that partitions the directed line segment in a
larisa86 [58]

Answer:

Point (1,8)  

Step-by-step explanation:

We will use segment formula to find the coordinates of point that will partition our line segment PQ in a ratio 3:1.

When a point divides any segment internally in the ratio m:n, the formula is:

[x=\frac{mx_2+nx_1}{m+n},y= \frac{my_2+ny_1}{m+n}]

Let us substitute coordinates of point P and Q as:

x_1=-8,

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[x=\frac{(3*4)+(1*-8)}{3+1},y=\frac{(3*12)+(1*-4)}{3+1}]

[x=\frac{12-8}{4},y=\frac{36-4}{4}]

[x=\frac{4}{4},y=\frac{32}{4}]

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Therefore, point (1,8) will partition the directed line segment PQ in a ratio 3:1.

   

7 0
3 years ago
At the fair, the ratio of males to females was 4:5. If there are 180 people at the fair, how mamy males are there?​
Setler79 [48]

Answer:

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3 0
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Step-by-step explanation:

3+√5+3√5+5

=6√5+5

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3 years ago
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liraira [26]
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