Answer:
about 11.5 cm.
Step-by-step explanation:
I know the measurement of the other leg is about 11.5 cm. I know because I used the Pythagorean theorem.
a^2+b^2=c^2.
"a" and "b" are the values of the legs of the triangle, while "c" is the measure of the hypotenuse. We know that 8cm is the measure of one of the legs, and 14 cm is a measure of the hypotenuse.
8^2+b^2=14^2 simplified: 64+b^2=196
Then, I subtracted 64 on both sides, so I would have "b" by itself.
b^2=132
Next, I found the square root of both b^2 and 132, so I would find the true value of "b."
b=11.4891252931
So, the measure of the other leg rounded to the nearest tenth is about 11.5.
9) C.
10)A.
11) $75
Those are all the answers that you needed.
Their is not a lot of information but I think it is 12*24=288
Answer:
a. False
b. True
Step-by-step explanation:
Given that:
The sample size of the college student n = 100
The population of student that participated p = 38
We are to identify from the following statement if it is true or false.
From part a;
It is false since the random samples not indicate the population perfectly. As such we can't conclude that the proportion of students at this college who participate in intramural sports is 0.38.
The statement in part b is true because the sampling variation, random samples also do not indicate the population perfectly but it is close to be 0.38. Thus, it is suitable to conclude that the proportion of students at this college who participate in intramural sports is likely to be close to 0.38, but not equal to 0.38.
Answer:
see below
Step-by-step explanation:
<h3>Given</h3>
- Distance is 142.2 m, correct to 1 decimal place
- Time is 7 seconds, correct to nearest second
<h3>To find:</h3>
- Upper bound for the speed
<h3>Solution </h3>
<em>Upper bound for the speed = upper bound for distance/lower bound for time</em>
- Upper bound for distance = 142.25 m (added 0.1/5 = 0.05)
- Lower bound for time = 6.5 seconds (subtracted 1/2 = 0.5)
<u>Then, the speed is:</u>
- 142.25/6.5 = 21.88 m/s
- 21.88 = 21.9 m/s correct to 1 decimal place
- 21.88 = 22 m/s correct to nearest m/s
