Answer:
, x = 6 ton
Step-by-step explanation:
The truck can be filled with a total of 20 ton.
There are already 14 ton inside the truck, so if we call x the weight of goods that we can still add into the truck, we know that (x+14) must be equal at most at 20. Therefore, the inequality becomes:
Solving it, we find
which means that the most amount of goods that could be added to the truck is 6 tons.
Answer: Well, do you mean the whole value? If so... it's two-hundred and eighty. If you mean the individuals, then the two is two-hundred, the 8 is eighty.
Step-by-step explanation:
11/3 - 2/3 = 9/3 = 3 so he spent 3 more hours reading on saturday than on friday
Hope this helps!
Answer:
10
Step-by-step explanation:
d = √(x2 -x1)² + (y2 - y1)²
√(-6 - 0)² + [1 - (-7)]²
√(-6)² + (8)²
√(36) + (64)
√100
= 10
Answer:
A.) gf(x) = 3x^2 + 12x + 9
B.) g'(x) = 2
Step-by-step explanation:
A.) The two given functions are:
f(x) = (x + 2)^2 and g(x) = 3(x - 1)
Open the bracket of the two functions
f(x) = (x + 2)^2
f(x) = x^2 + 2x + 2x + 4
f(x) = x^2 + 4x + 4
and
g(x) = 3(x - 1)
g(x) = 3x - 3
To find gf(x), substitute f(x) for x in g(x)
gf(x) = 3( x^2 + 4x + 4 ) - 3
gf(x) = 3x^2 + 12x + 12 - 3
gf(x) = 3x^2 + 12x + 9
Where
a = 3, b = 12, c = 9
B.) To find g '(12), you must first find the inverse function of g(x) that is g'(x)
To find g'(x), let g(x) be equal to y. Then, interchange y and x for each other and make y the subject of formula
Y = 3x + 3
X = 3y + 3
Make y the subject of formula
3y = x - 3
Y = x/3 - 3/3
Y = x/3 - 1
Therefore, g'(x) = x/3 - 1
For g'(12), substitute 12 for x in g' (x)
g'(x) = 12/4 - 1
g'(x) = 3 - 1
g'(x) = 2.
