Use the Euclidean algorithm to express 1 as a linear combination of 
and 
.
a. 
because
77 = 1*52 + 25
52 = 2*25 + 2
25 = 12*2 + 1
so we can write
1 = 25 - 12*2 = 25*25 - 12*52 = (77 - 52)(77 - 52) - 12*52 = 77^2 - 2*52*77 + 52^2 - 12*52
Taken modulo 77 leaves us with
b. First, 
, so really we're looking for the inverse of 25 mod 52. We've basically done the work in part (a) already:
1 = 25*25 - 12*52
Taken modulo 52, we're left with
c. The EA gives
71 = 1*53 + 18
53 = 2*18 + 17
18 = 1*17 + 1
so we get
1 = 18 - 17 = 3*18 - 53 = 3*71 - 4*53
so that taken module 71, we find
d. Same process as with (b). First we have 
, and we've already shown that
1 = 3*18 - 53
which means, taken modulo 53, that
Yes, ode45 can be used for higher-order differential equations. You need to convert the higher order equation to a system of first-order equations, then use ode45 on that system.
For example, if you have
... u'' + a·u' + b·u = f
you can define u1 = u, u2 = u' and now you have the system
... (u2)' + a·u2 + b·u1 = f
... (u1)' = u2
Rearranging, this is
... (u1)' = u2
... (u2)' = f - a·u2 - b·u1
ode45 is used to solve each of these. Now, you have a vector (u1, u2) instead of a scalar variable (u). A web search regarding using ode45 on higher-order differential equations can provide additional illumination, including specific examples.
Answer:
Yes they are congruent
they are congruent by SSS rule that is Side Side Side rule
AD = CD (given side) in the question itself
AB = CB (given side) in the question itself
Db = BD (common side)
thats why by SSS rule they are congruent
Answer:
Factors :- (x - 5) (x + 2)
Values :- x = 5, x = -2
Step-by-step explanation:
= > x^2 - 3x - 10 = 0
= > x^2 - (5 - 2)x - 10 = 0
= > x^2 - 5x + 2x - 10 = 0
= > x (x - 5) + 2 (x - 5) = 0
= > (x + 2) ( x - 5) = 0...factors
= > x = 5, - 2...values
<h2>Hope it helps you!! </h2>
