Answer:
The first 5 terms are 2, 5, 8, 11, 14.
Step-by-step explanation:
- You use the formula to find out each term.
- f(n)=3n-1 starting with n=1. If n=1 that is the 1st term, if n=2 that is the 2nd term, and so on. n means what number term it is.
- Now to find each term:
- n=1: f(1)= 3(1)-1= 3-1= 2 The 1st term is 2
- n=2: f(2)= 3(2)-1= 6-1= 5 The 2nd term is 5
- n=3: f(3)= 3(3)-1= 9-1=8 The 3rd term is 8
- n=4: f(4)= 4(3)-1= 12-1= 11 The 4th term is 11
- n=5: f(5)= 5(3)-1= 15-1= 14 The 5th term is 14
So the first 5 terms are 2,5,8,11,14
C. Yes because it passes the vertical line test
Answer:
$11543.63
Step-by-step explanation:
<u>Plug information into A=P(1+r/n)^nt</u>
13000 = P(1+(.04/2))^(2*3)
13000 = P(1.02)^6
<u>Isolate P</u>
13000/(1.02^6) = P
P = $11543.63
Step-by-step explanation:
sol;
x+1=y...(1)
3y-7=2x....(2)
or, 3(x+1)-72x [from (1)]
or, 3x+3-7=2x
or, 3x-2x=7-3
x=4
now,
putting the value of x in (1)
y=x+1
=4+1
=5
PR and SQ are the diagonal of PQRS.