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3 years ago

I don't get this word problem someone help

Mathematics

1 answer:

amm18123 years ago

4 0

If the car were 6 feet tall, the model would be 1in tall. so if the model is .75in then you would do 75% of 6, so therefore, you will get 4.5.

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Solve, finding all the solutions in [O, 2pi).<br> cot(x) cos(x) + cot(x) = 0

KATRIN_1 [288]

Step-by-step explanation:

cot(x) cos(x) + cot(x) = 0

cot(x) (cos(x) + 1) = 0

cot(x) = 0 or cos(x) = -1

cot(x) = 0

x = π/2, 3π/2

x ≠ 0, π

cos(x) = -1

x = π

Therefore, the answer is x = π/2, 3π/2.

6 0

4 years ago

Which is the following is the set of real zeros of the function f(x) = (x3 + 1000)(x4 - 160,000)?

marusya05 [52]

Answer:

A. { -20, -10, 20 }

Step-by-step explanation:

Given:

The function is given as:

$f(x)=(x^3+1000)(x^4-160000)$

Let us simplify the function.

First, we use the identity $a^3+b^3=(a+b)(a^2-ab+b^2)$

$x^2+1000= x^3+10^3=(x+10)(x^2-10x+10^2)\\x^3+1000=(x+10)(x^2-10x+100)$

Next, we use the identity $a^4-b^4=(a-b)(a+b)(a^2+b^2)$

$x^4-160000=x^4-20^4=(x-20)(x+20)(x^2+20^2)=(x-20)(x+20)(x^2+400)$

Now, the function can be rewritten as:

$f(x)=(x+10)(x^2-10x+100)(x-20)(x+20)(x^2+400)$

Now, the zeros are those values of $x$ for which $f(x)=0$

Now, for $f(x)=0$ , we must have either of the factors 0.

$x+10=0\\x=-10$

$x-20=0\\x=20\\\\x+20=0\\x=-20$

The factors $x^2-10x+100$ and $x^2+400$ can have no zeros as the first one has imaginary roots and second one is always greater than 0 irrespective of the $x$ values.

So, the possible set of zeros are { -20, 10, 20 }.

6 0

4 years ago

a blueprint has a scale of 1/8 in = 1 foot the drawing shows width of a window to be 3/4 inches wide what is the actual of the w

kobusy [5.1K]

6 Feet.

Divide the width of the window in the blueprint by the set scale, 1/8.

8 0

3 years ago

Help i don’t know the answer???

oee [108]

It’s D the answer is 27

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3 years ago

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artcher [175]

Answer: B

Step-by-step explanation:

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3 years ago

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