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2 years ago

The vertex is (-8,- 4) and the parabola opens up. The domain of f is?

Mathematics

1 answer:

sveticcg [70]2 years ago

7 0

Domain is the left and right values, which means any parabola opening up or down will have a domain of (-∞, ∞)

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Express this number in scientific notation: 0.0002077

RSB [31]

Given the number:

0.0002077

Let's express in scientific notation.

To express the number in scientific notation, move the decimal point so that there is only one non-zero number to the left of the decimal point.

Then, the number of decimal places you move will be the exponent on 10.

If the decimal point is moved to the right, the exponent will be negative.

If the decimal pointt is moved to the left, the exponent will be positive.

In this case the decimal point will be moved to the right.

Using this description, we have the scientific notation below:

$undefined$

7 0

1 year ago

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PLEASE ANSWER THIS QUESTION RIGHT AND THE ANSWER CHOICES ARE IN THE TOP Elize is scuba diving in plans to leisurely Ascend to

yulyashka [42]

anyone know that answer ?

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3 years ago

What must be added to both sides of the equation x – 12 = 15 to isolate the variable?

pishuonlain [190]

Answer:

c. 12

Step-by-step explanation:

To isolate the variable, you need to cancel out whatever's on the same side of the variable by using the inverse of the operation.

Hope this helps!! Have an awesome day φ(*^0^)

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3 years ago

How can i prove this property to be true for all values of n, using mathematical induction.

chubhunter [2.5K]

Proof -

So, in the first part we'll verify by taking n = 1.

$\implies \: 1 = {1}^{2} = \frac{1(1 + 1)(2 + 1)}{6}$

$\implies{ \frac{1(2)(3)}{6} }$

$\implies{ 1}$

Therefore, it is true for the first part.

In the second part we will assume that,

$\: { {1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} = \frac{k(k + 1)(2k + 1)}{6} }$

and we will prove that,

$\sf{ \: { {1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k + 1)(k + 1 + 1) \{2(k + 1) + 1\}}{6}}}$

$\: {{1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k + 1)(k + 2) (2k + 3)}{6}}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{k (k + 1) (2k + 1) }{6} + \frac{(k + 1) ^{2} }{6}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{k(k+1)(2k+1)+6(k+1)^ 2 }{6}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)\{k(2k+1)+6(k+1)\} }{6}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)(2k^2 +k+6k+6) }{6}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)(2k^2+7k+6) }{6}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)(k+2)(2k+3) }{6}$

Henceforth, by using the principle of mathematical induction 1²+2² +3²+....+n² = n(n+1)(2n+1)/ 6 for all positive integers n.

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8 0

2 years ago

Write an expression for the sequence of operations described below.

SSSSS [86.1K]

(3-6)-p

It says your subtracting 6 from 3 which is (3-6) and it says "then" that's why we put parentheses and then put "-p"

5 0

3 years ago

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