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vovikov84 [41]
3 years ago
11

(-4, 6) and (3,-7) how do I solve this? ​

Mathematics
1 answer:
sertanlavr [38]3 years ago
6 0

Answer: - 13/7

Mark me Brainliest

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Which table has a constant of proportionality between y and 2 of 0.3?
finlep [7]

Answer:

The question is unclear. Please provide the table.

7 0
3 years ago
I'm going to test you (deff not for my hw)
Alja [10]

The first sequence, it is increase +1 for every number, because 2-3 is 1, 3 - 5 is 2, and 5 - 8 is 3. So, lets add 4 to 8, and we will know the next number of the sequence.

4 + 8 = 12

So, the next number in the first sequence is:

1, 1, 2, 3, 5, 8, 12

Second Sequence:

The second equation is doing exactly the same thing (it increases by 1 every number it goes) just this one is decreasing.

Proof: 26 - 24 is 2, 24 - 21 is 3, and 21 - 17 is 4.

Lets subtract 5 to 17 to know the next number.

17 - 5 = 12

So our next number is:

26, 24, 21, 17, 12

4 0
3 years ago
Loan Amount: $13,000 Method of payment: discount basis Amount of Interest: $625 Term of loan: 1 year Effective Rate of Interest
Gekata [30.6K]
<span>Loan Amount: $13,000
Method of payment: discount basis
Amount of Interest: $625
</span><span> Term of loan: 1 year
</span>
∴ Rate if interest = \frac{Amount \ of \ Interest}{Loan \ Amount} *100
Rate =  \frac{625}{13,000} *100 = \framebox {4.8 \%}

So, the correct answer is option (1) 4.8
<span />
3 0
3 years ago
Is 6 - 1/2 = 4 1/2? if not can you explain?
Dmitry [639]

It is not correct. "6-1/2" is just 1/2 less than 6. This is simply 5 1/2. So, 4 1/2 is incorrect.

7 0
3 years ago
What is the perimeter of a triangle with vertices located at (1, 3), (2, 6), and (0, 4), rounded to the nearest hundredth?
lianna [129]
The perimeter of a triangle is the sum of the lengths of all sides.
Using the distance formula d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} calculate the lengths of the sides and then add them up.

A=(1,3) \\&#10;B=(2,6) \\&#10;C=(0,4) \\ \\&#10;\overline{AB}=\sqrt{(2-1)^2+(6-3)^2}=\sqrt{1^2+3^2}=\sqrt{1+9}=\sqrt{10} \\&#10;\overline{AC}=\sqrt{(0-1)^2+(4-3)^2}=\sqrt{(-1)^2+1^2}=\sqrt{1+1}=\sqrt{2} \\&#10;\overline{BC}=\sqrt{(0-2)^2+(4-6)^2}=\sqrt{(-2)^2+(-2)^2}=\sqrt{4+4}=\sqrt{4 \times 2}= \\&#10;=2\sqrt{2} \\ \\&#10;P=\overline{AB}+\overline{AC}+\overline{BC}=\sqrt{10}+\sqrt{2}+2\sqrt{2}=\sqrt{10}+3\sqrt{2} \approx 7.40

The answer is A.
5 0
3 years ago
Read 2 more answers
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