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MrRa [10]
4 years ago
13

Team infinite dimensions canoed 15 3/4 miles in 3 hours. what was their average rate of speed in miles per hour?

Mathematics
2 answers:
Romashka [77]4 years ago
5 0

Answer:

5.25 or 5 1/4 mph.

Step-by-step explanation:

<em>Let us recall that,</em>

<em>The Average speed = The total time/total distance covered</em>

<em> Team infinite dimensions is canoed 15 3/4 Miles</em>

<em>The Hours from the example =3</em>

<em>So,</em>

<em>15 3/4 / 3 = 63/4 / 3 </em>

<em>which is  63/12 = 5.25 </em>

<em> or in another way, we can also arrive at the same solution which is,</em>

<em>15 3/4=15.75 </em>

<em>15.75 miles/3 hours=5.25 or 5 1/4 mph.</em>

<em>the average speed in miles per hour is, 5.25 miles/hour</em>

Allushta [10]4 years ago
3 0

Average speed = total distance/total time

15 3/4  / 3 = 63/4 / 3 = 63/12 = 5.25

so, their average speed was 5.25 miles/hour

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8 0
3 years ago
Joe sold a total of 10 baked goods. Each cookie costs $1.25 and each brownie costs $2.50. Joe made $20 at the bake sale. How man
AURORKA [14]

Answer:

4 cookies

Step-by-step explanation:

Let the number of cookies he sold be c and that of brownies be b.

Assuming that brownies and cookies are the only type of baked goods sold,

b +c= 10 -----(1)

Amount of money received= $20

b(cost of brownie) +c(cost of cookie)= $20

2.50b +1.25c= 20 -----(2)

From (1): b= 10 -c -----(3)

Substitute (3) into (2):

2.50(10 -c) +1.25c= 20

Expand:

2.50(10) +2.50(-c) +1.25c= 20

25 -2.50c +1.25c= 20

-1.25c +25= 20

Being constants to 1 side:

-1.25c= 20 -25

-1.25c= -5

c= -5 ÷(-1.25)

c= 4

Thus, Joe sold 4 cookies.

8 0
3 years ago
PLSSS ASAPPP HELPPPPPP!!!
aksik [14]
Send me a photo and ill solve it because you gave me nothing to work with lol
4 0
3 years ago
Need help with this question
mixer [17]

Hey there!!

How do we find the equation of a line ?

Ans : We take the slope and the y - intercept and get them together.

How do you find slopes?

Ans - In order to find slop, we will need to use the slop formula which is

( y₂ - y₁ ) / ( x₂ - x₁ )

The two points shown in the above question are

( 4 , -8 ) and ( 8 , 5 )

y₂ = 5 , y₁ = -8 and x₂ = 8 , x₁ = 4

Now plug in the values:

( 5 + 8 ) / ( 8 - 5 )

13 / 3

Hence, the slope is 13/3

The basic formula : y = mx + b

Where b is the y-intercept and m is the slope.

We have found the slope, hence, the formula would become

... y = 13/3 x + b

Now take a coordinate and substitute it .

I will take ( 8 , 5 )

x = 8 and y = 5

Now plug in the values

... 5 = 13/3 × 5 + b

... 5 = 65/3 + b

Subtract 65/3 on both sides

... 5 - 65/3 = b

... -50/3 = b

Hence, the y-intercept is -50/3

Now plug in all the values to get the total equation...

The final equation : y = 13x/3 - 50/3

... y = 13x - 50 / 3

Hope my answer helps!!

3 0
3 years ago
Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. y = 7x6, y
IgorC [24]

Answer:

The volume is \frac{490\pi}{39} cubic units.

Step-by-step explanation:

The given curve is

y=7x^6

The given line is

y=7x

Equate both the functions to find the intersection point of both line and curve.

7x^6=7x

7x^6-7x=0

7x^6-7x=0

7x(x^5-1)=0

7x=0\rightarrow x=0

x^5-1=0\rightarrow x=1

According to washer method:

V=\pi \int_{a}^{b}[f(x)^2-g(x)^2]dx

Using washer method, where a=0 and b=1, we get

V=\pi \int_{0}^{1}[(7x)^2-(7x^6)^2]dx

V=\pi \int_{0}^{1}[49x^2-49x^{12}]dx

V=49\pi \int_{0}^{1}[x^2-x^{12}]dx

V=49\pi [\frac{x^3}{3}-\frac{x^{13}}{13}]_0^1

V=49\pi [\frac{1^3}{3}-\frac{1^{13}}{13}-(0-0)]

V=49\pi [\frac{1}{3}-\frac{1}{13}]

V=49\pi (\frac{13-3}{39})

V=49\pi (\frac{10}{39})

V=\frac{490\pi}{39}

Therefore the volume is \frac{490\pi}{39} cubic units.

5 0
3 years ago
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