The answer is 87 hopes this helps
Answer: She started with $160.
It will take 6 weeks before she has less than half of what she originally invested.
Step-by-step explanation:
If her money is decreasing in value by 11% each week, it means that the rate at which it is decreasing is exponential.
We would apply the formula for exponential decay which is expressed as
A = P(1 - r)^t
Where
A represents the value of the investment after t weeks.
t represents the number of weeks.
P represents the initial value of the investment.
r represents rate of depreciation.
From the information given,
A = $142.40
r = 11% = 11/100 = 0.11
t = 1
Therefore
142.40 = P(1 - 0.11)^1
142.40 = P(0.89)
P = 142.4/0.89
P = 160
For her to have half of what she invested originally, then
80 = 160(0.89)^t
80/160 = (0.89)^t
0.5 = (0.89)^t
Taking log of both sides to base 10
Log 0.5 = log0.89^t = tlog0.89
- 0.3010 = - 0.051t
t = - 0.3010/- 0.051
t = 5.9
Approximately 6 weeks
Answer:
<h2>Length = 13 in.
</h2>
Step-by-step explanation:
perimeter of a rectangle (P) = 2L + 2W
where;
P = 42 in.
Length (L) = 5 + W
Find:
length (L) of the rectangle
solution:
P = 2L + 2W
42 = 2(5 + W) + 2W
42 = 10 + 2W + 2W
42 - 10 = 4W
32 = 4W
W = 32/4
W = 8
Length (L) = 5 + W
= 5 + 8
= 13 in
proof:
42 = 2(13) + 2(8)
42 = 42 in
Answer:
Yes it is a function
Step-by-step explanation:
We have to check the ordered pairs to find out if given relation is a function or not.
In an ordered pair, the first element represents the input and the second element represents the output.
The set of inputs is domain and output is range.
For a relation to be function, there should be no repetition in domain i.e there should be unique pairs of input and output.
In the given relation, the domain is {3,5,-1,-2}.
No element is repeated hence it is a function ..
we are given
Since, we have to solve for m
so, we will try to isolate m on anyone side
so, firstly , we will get rid of 1/6
so, we can multiply both sides by 6
now, we can simplify right side
now, we can multiply them
and we get
...........Answer
