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juin [17]
2 years ago
8

Ty very much! Please help? :))

Mathematics
1 answer:
wlad13 [49]2 years ago
4 0

Answer:

<em>Exact Form: </em>

\frac{8}{3}

<em>Decimal Form: </em>

2.6

<em>Mixed Number Form: </em>

2\frac{2}{3}

Hope this helps :)

<em>-ilovejiminssi♡</em>

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PLEASE HELP WILL GIVE BRAINLIEST!!
NemiM [27]

Answer:

p<7

Step-by-step explanation:

$5 per pound

7 pounds equals $35

$5p<$35

p<35/5

p<7

7 0
3 years ago
Bianca’s Bike Shop made a profit of $54,000 last year. This year, the profits were 250% of last year’s. How much profit did Bian
Alexandra [31]
Since the percent increase is bigger than 100%, it definitely has to be more than 54,000.

so let's break this down:
250%= 100% + 100% + 50%

we know 100% is the whole price so if there are 2 100% we have to multiply the price by two!!!
54,000•2 = 108,000

now, 50% is half of the whole price, divide the price by two:
54,000÷2= 27,000

so add your results and you will get this!
108,000+27,000= 135,000
4 0
3 years ago
Read 2 more answers
6. Which of the following is a unit of volume?<br> liter<br> foot<br> square meter<br> milligram
Ostrovityanka [42]

liter

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4 0
2 years ago
Got them.... I think the war is finally over..
lisabon 2012 [21]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
A disk with radius 3 units is inscribed in a regular hexagon. Find the approximate area of the inscribed disk using the regular
Oksi-84 [34.3K]

Answer:

The approximate are of the inscribed disk using the regular hexagon is A=18\sqrt{3}\ units^2

Step-by-step explanation:

we know that

we can divide the regular hexagon into 6 identical equilateral triangles

see the attached figure to better understand the problem

The approximate area of the circle is approximately the area of the six equilateral triangles

Remember that

In an equilateral triangle the interior measurement of each angle is 60 degrees

We take one triangle OAB, with O as the centre of the hexagon or circle, and AB as one side of the regular hexagon

Let

M  ----> the mid-point of AB

OM ----> the perpendicular bisector of AB

x ----> the measure of angle AOM

m\angle AOM =30^o

In the right triangle OAM

tan(30^o)=\frac{(a/2)}{r}=\frac{a}{2r}\\\\tan(30^o)=\frac{\sqrt{3}}{3}

so

\frac{a}{2r}=\frac{\sqrt{3}}{3}

we have

r=3\ units

substitute

\frac{a}{2(3)}=\frac{\sqrt{3}}{3}\\\\a=2\sqrt{3}\ units

Find the area of six equilateral triangles

A=6[\frac{1}{2}(r)(a)]

simplify

A=3(r)(a)

we have

r=3\ units\\a=2\sqrt{3}\ units

substitute

A=3(3)(2\sqrt{3})\\A=18\sqrt{3}\ units^2

Therefore

The approximate are of the inscribed disk using the regular hexagon is A=18\sqrt{3}\ units^2

6 0
3 years ago
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