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SVETLANKA909090 [29]
4 years ago
13

1200-5(3x+30)=600 show the steps to solve this problem

Mathematics
2 answers:
jasenka [17]4 years ago
8 0

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{x = 30}}}}}

Step-by-step explanation:

\sf{1200 - 5(3x + 30) = 600}

Distribute 5 through the parentheses

\dashrightarrow{ \sf{1200 - 15x - 150 = 600}}

Subtract the numbers: 150 from 1200

\dashrightarrow{ \sf{ - 15x  + 1050 = 600}}

Move 1050 to right hand side and change it's sign

\dashrightarrow{ \sf{ - 15x = 600 - 1050}}

Subtract 1050 from 600

\dashrightarrow{ \sf{ - 15x = 450}}

Divide both sides of the equation by -15

\dashrightarrow{ \sf{ \frac{ - 15x}{ - 15}  =  \frac{ - 450}{ - 15} }}

Calculate

\dashrightarrow{ \sf{x = 30}}

Hope I helped!

Best regards! :D

Romashka [77]4 years ago
3 0

Answer:

x=+30

Step-by-step explanation:

1200-5(3x+30)=600

We move all terms to the left:

1200-5(3x+30)-(600)=0

We add all the numbers together, and all the variables

-5(3x+30)+600=0

We multiply parentheses

-15x-150+600=0

We add all the numbers together, and all the variables

-15x+450=0

We move all terms containing x to the left, all other terms to the right

-15x=-450

x=-450/-15

x=+30

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6. Suppose that a fair coin is tossed 2 times, and the result of each toss (H or T) is recorded.
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Answer:

a) S= {HH, HT, TH, TT}

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And we have the following table:

X     |     0   |     1   |      2

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Step-by-step explanation:

Let's define first some notation

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T= represent tails for the coin tossed

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The sampling space on this case is given by:

S= {HH, HT, TH, TT}

b. For this chance experiment, give the probability distribution for the random variable of the total number of heads observed.

The possible values for the number of heads are X=0,1,2. If we assume a fair coin then the probability of obtain heads is the same probability of obtain tails and we can find the distribution like this:

P(X=0) = (2C0) (0.5)^0 (1-0.5)^{2-0}= 0.25

P(X=1) = (2C1) (0.5)^1 (1-0.5)^{2-1}= 0.5

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