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Nookie1986 [14]
2 years ago
12

Add. Write your answer as a fraction or as a whole or mixed number. 3 9 10 + 3 11 11

Mathematics
1 answer:
kherson [118]2 years ago
3 0

we have

10 3/11 + 3 9/11=(10+3)+(3/11+9/11)=13+(12/11)=13=(13=(

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Find the value of yy in each equation. Explain how you determined the value of y.
Hitman42 [59]

Answer:

a) 3

b) 9

c) 81

d) x

Step-by-step explanation:

We know the properties of log function as:

1) log(AB) = log(A) + log(B)

2) \log(\frac{A}{B}) = \log(A)+\log(B)

3) log(aᵇ) = b × log(a)

also,

4) \log_b(a)=\frac{\log(a)}{\log(b)}

Given:

a. y = 3^{\log_3(3)}

Now,

taking log both sides, we get

log(y) = \log(3^{\log_3(3)})

using 3, we get

log(y) = log₃(3) × log(3)

using 4, we get

log(y) =  \frac{\log(3)}{\log(3)} × log(3)

or

log(y) =  1 × log(3)

taking anti-log both sides

y = 3

b. y = 3^{log_3(9)}

Now,

taking log both sides, we get

log(y) = \log(3^{\log_3(9)})

using 3, we get

log(y) = log₃(9) × log(3)

using 4, we get

log(y) =  \frac{\log(9)}{\log(3)} × log(3)

or

log(y) = log(9)

taking anti-log both sides

y = 9

c. y = 3^{\log_3(81)}

Now,

taking log both sides, we get

log(y) = \log(3^{\log_3(81)})

using 3, we get

log(y) = log₃(81) × log(3)

using 4, we get

log(y) =  \frac{\log(81)}{\log(3)} × log(3)

or

log(y) =  log(81)

taking anti-log both sides

y = 81

d. y = 3^{\log_3(x)}

Now,

taking log both sides, we get

log(y) = \log(3^{\log_3(x)})

using 3, we get

log(y) = log₃(x) × log(3)

using 4, we get

log(y) =  \frac{\log(x)}{\log(3)} × log(3)

or

log(y) =  log(x)

taking anti-log both sides

y = x

3 0
3 years ago
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