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sladkih [1.3K]
3 years ago
11

I'm really confused on how to do this :/ can I get some help ? :/

Mathematics
1 answer:
Sphinxa [80]3 years ago
7 0
Hello!
Circular problems are the worst, am I right?
So as it says, A (Area) = \pi (Pi) r^{2} (Radius Squared.)
So Area = Pi times Radius Squared. The radius is the length from the center of a circle to any "edge" of the circle. So 1.5 feet is the radius.
1.5 Times 1.5 is 2.25. Pi is around 3.14. So 2.25 times 3.14. This is 7.065.
You're trying to find that red part. So you divide 7.065 by 4. It equals 1.76625.
Rounded to the nearest hundreth, it is 1.77.
Your answer is 1.77 ft^{2}

I hope I helped!
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The link is attached do your best to figure it out.
inysia [295]

Answer:

answer is A

Step-by-step explanation:

-2.5 and -10 equals -12.5.

(and) refers to addition in math so your adding two negatives.

6 0
2 years ago
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When you cut a pyramid straight up and down, what shape is your cross section?
aleksandr82 [10.1K]

Answer:

The cross section of a pyramid that is perpendicular to the base will be a triangle.

Step-by-step explanation:

5 0
3 years ago
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In Exercises 40-43, for what value(s) of k, if any, will the systems have (a) no solution, (b) a unique solution, and (c) infini
svet-max [94.6K]

Answer:

If k = −1 then the system has no solutions.

If k = 2 then the system has infinitely many solutions.

The system cannot have unique solution.

Step-by-step explanation:

We have the following system of equations

x - 2y +3z = 2\\x + y + z = k\\2x - y + 4z = k^2

The augmented matrix is

\left[\begin{array}{cccc}1&-2&3&2\\1&1&1&k\\2&-1&4&k^2\end{array}\right]

The reduction of this matrix to row-echelon form is outlined below.

R_2\rightarrow R_2-R_1

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\2&-1&4&k^2\end{array}\right]

R_3\rightarrow R_3-2R_1

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&3&-2&k^2-4\end{array}\right]

R_3\rightarrow R_3-R_2

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&0&0&k^2-k-2\end{array}\right]

The last row determines, if there are solutions or not. To be consistent, we must have k such that

k^2-k-2=0

\left(k+1\right)\left(k-2\right)=0\\k=-1,\:k=2

Case k = −1:

\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-1-2\\0&0&0&(-1)^2-(-1)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-3\\0&0&0&-2\end{array}\right]

If k = −1 then the last equation becomes 0 = −2 which is impossible.Therefore, the system has no solutions.

Case k = 2:

\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&2-2\\0&0&0&(2)^2-(2)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&0\\0&0&0&0\end{array}\right]

This gives the infinite many solution.

5 0
3 years ago
Wilson did a survey to find the average shoe size of the students in his class. He asked the following question: What is the sho
nasty-shy [4]
Wilson's question is not a statistical question because the students my not a have tall person in their class
5 0
3 years ago
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I’m confused on this one
Mandarinka [93]

Remark

If the lines are parallel then triangle RQS will be similar to triangle RTP


From that, all three lines in one triangle will bear the same ratio to all three lines of the second triangle.


Givens

PQ = 8

QR = 5

RS = 15

ST = x + 3


Ratio

QR/RP = RS/RT


Sub and solve

RP = 5 + 8

RP = 13


RT = 15 + x + 3

RT = 18 + x


5/13 = 15 / (18 + x) Cross multiply

5(18 + x) = 195 Remove the brackets on the left.

90 + 5x = 195 Subtract 90 from both sides.

5x = 105 Divide by 5

x = 105/5

x = 21 Answer <<<<<<<

3 0
3 years ago
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