The volume of the balloon when the mass of oxygen gas is decreased to 50g is 50L.
We will use the ideal gas equation-
<u>PV=nRT</u>
P=Pressure
V=volume
n=no. of moles
T=temperature
In this question temperature and pressure will remains constant then the above equation can be rewritten as-
where V1= initial volume of the balloon
V2= volume of the balloon when the mass of oxygen gas is decreased to 50g
now, substitute the values in the above equation-
100/3.12=V2/1.56
hence, the volume of the balloon when the mass of oxygen gas is decreased to 50g is 50L.
learn more about the ideal gas equation here:
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D. A town has started a new recycling and composting program
Ok let me explain the procedure to you:
The buffer solution is like this:
pH = pKa + log [salt]/[acid]
4 = 4.20 + log [salt] / [acid]
-0.20 = log [salt]/[acid]
If you <span>Solve for [salt]/[acid]
This gives ratio of moles.
</span><span>Take amount of acid be x L and then amount of salt will be 0.1-x
Now molarity*volume=number of moles
</span>I know that with this you will be able to get to the result. Hope this helps
Answer:
ΔE = 73 J
Explanation:
By the first law of thermodynamics, the energy in the system must conserved:
ΔE = Q - W
Where ΔE is the internal energy, Q is the heat flow (positive if it's absorbed by the system, and negative if the system loses heat), and W is the work (positive if the system is expanding, and negative if the system is compressing).
So, Q = + 551 J, and W = + 478 J
ΔE = 551 - 478
ΔE = 73 J
Molarity =wt/M.wt * 1000/V
=> 1.77 = wt/180 * 1000/555
> wt = 1.77 * 180*555 /1000 = 176.823 g
