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MrRissso [65]
3 years ago
10

A cylinder and piston assembly (defined as the system) is warmed by an external flame. The contents of the cylinder expand, doin

g work on the surroundings by pushing the piston outward against the external pressure. If the system absorbs 551 J of heat and does 478 J of work during the expansion, what is the value of ΔE?
Chemistry
1 answer:
melomori [17]3 years ago
3 0

Answer:

ΔE = 73 J

Explanation:

By the first law of thermodynamics, the energy in the system must conserved:

ΔE = Q - W

Where ΔE is the internal energy, Q is the heat flow (positive if it's absorbed by the system, and negative if the system loses heat), and W is the work (positive if the system is expanding, and negative if the system is compressing).

So, Q = + 551 J, and W = + 478 J

ΔE = 551 - 478

ΔE = 73 J

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Calculemos la formula empirica y molecular de carbonato de hierro Fe2(co3)3.Fe.38.3%C.12.3%.0.4 92% masa 292g
DENIUS [597]

Respuesta:

292 g / mol;

Por favor, consulte la explicación.

Explicación:

El número de átomos de cada elemento en el compuesto: Fe2 (co3) 3.

Fe = 2; C = 3; 0 = 3 * 3 = 9

Fe2 = 112 g / mol

C = 12 g / mol

O = 16 g /

Masa molecular = ((112 + (12 * 3) + (16 * 9)

= (112 + 36 + 144)

= 292 g / mol.

Total = 2 + 3 + 9 = 14

Fe2 = 112/292 * 100% = 38,356%

C = 36/292 * 100% = 12,328 * '

O = (16 * 9) / 292 * 100% = 49,32%

7 0
3 years ago
Using the example of an ambulance, explain the Doppler Effect. Infer why the doppler effect can or cannot occur in all waves. PL
kozerog [31]

Answer:

When the ambulance is coming towardss you the waves are smushed together and sound higher pitched but then it passes you and when tracveling away the waves are scretched out so the whee whoo sounds lower and that is because of the doppler effect

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3 years ago
What does all flexible objects have in common
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6 0
3 years ago
1. The equation for the reaction between zinc and aqueous copper(II) sulfate is shown.
Fed [463]

Answer:

The oxidation state of the reducing agent has changed from 0 to +2.

Explanation:

reducing agent is anything that loses electron or gains oxygen

in this case, zinc

3 0
3 years ago
What isotope is the product of the alpha (*2He) nuclear decay of Radon-222 (222U)?
NikAS [45]

Answer:

ⁿₐX => ²¹⁸₈₄Po

Explanation:

Let ⁿₐX be the isotope.

Thus, the equation can be written as follow:

²²²₈₆Rn —> ⁴₂α + ⁿₐX

Next, we shall determine the value of 'n' and 'a'. This can be obtained as follow:

222 = 4 + n

Collect like terms

222 – 4 = n

218 = n

Thus,

n = 218

86 = 2 + a

Collect like terms

86 – 2 = a

84 = a

Thus,

a = 84

ⁿₐX => ²¹⁸₈₄Po

²²²₈₆Rn —> ⁴₂α + ⁿₐX

²²²₈₆Rn —> ⁴₂α + ²¹⁸₈₄Po

3 0
2 years ago
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