The first step is to balance the equation:
<span>C3H8 + 5O2 ---> 3CO2 + 4H2O
Check the balance
element left side right side
C 3 3
H 8 4*2 = 8
O 5*2=10 3*2 + 4 = 10
Then you have the molar ratios:
3 mol C3H8 : 5 mol O2 : 3 mol CO2 : 4 mol H2O
Now you have 40 moles of O2 so you make the proportion:
40.0 mol O2 * [3 mol CO2 / 5 mol O2] = 24.0 mol CO2.
Answer: option D. 24.0 mol CO2
</span>
Answer:
The alkali metals are the highly electropositive metals. Highly electropositive metals cannot be extraction carbon reduction process, because these metals do not react with carbon
Explanation:
Moles of NH₃ : = 7.059
<h3>Further explanation</h3>
Given
120 g NH₃
Required
moles NH₃
Solution
The mole is the number of particles contained in a substance
<em>1 mol = 6.02.10²³
</em>
Moles can also be determined from the amount of substance mass and its molar mass
Mol = mass : Molar mass
So for 120 g (molar mass of NH₃ = 17 g/mol) :
= 120 g : 17 g/mol
= 7.059
