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amid [387]
2 years ago
10

A star is observed from two positions of Earth in its orbit, in summer and winter. Which of these is the best method to calculat

e the approximate distance of the star from Earth? measure the parallax and use it in calculations measure the red shift of emitted light and use it in calculations use doppler effect to calculate the shift in light traveling from star to Earth in winter use doppler effect to calculate the shift in light traveling from star to Earth in summer
Chemistry
1 answer:
Fantom [35]2 years ago
6 0

Answer:

D. Calculate the variations in the potions of the star due to movement of Earth in its orbit

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Does wasting water also waste energy? Explain your reasoning.
77julia77 [94]

Answer:

Yes.

Explanation:

Wasting household water does not ultimately remove that water from the global water cycle, but it does remove it from the portion of the water cycle that is readily accessible and usable by humans. Also, "wasting" water wastes the energy and resources that were used to process and deliver the water.

6 0
3 years ago
Read 2 more answers
In some developing nations, the percentage of animal protein from fish in the diet can be as high as _____.
Makovka662 [10]

Answer:

20%

Explanation:

The fish consumption has had lot of variations in the past few centuries, most noticeably in the last century. Initially it was the richer countries that had population which was consuming the most animal protein from fish in the world, while the developing nations had less. Things have changed though, especially during the 1990's, when the developing nations experienced a rapid increase in the consumption of fish. This was largely due to the growing standard and the availability of fish, so in some of the developing nations the percentage of animal protein from fish reached around 20%.

5 0
3 years ago
Ethylenediamine (en) forms an octahedral complex with Ni2+(aq) with the formula [Ni(en)3]2+. Ni2+(aq) + 3 en ⇌ [Ni(en)3]2+(aq) K
yawa3891 [41]

Answer:

3.125\times 10^{-19} mol/L is the concentration of Ni^{2+}(aq) in the solution.

Explanation:

Ni^{2+}(aq) + 3 en\rightleftharpoons [Ni(en)_3]^{2+}(aq)

Concentration of nickel ion = [Ni^{2+}]=x

Concentration of nickel complex= [[Ni(en)_3]^{2+}]=\frac{0.16 mol}{2 L}=0.08 mol/L

Concentration of ethylenediamine = [en]=\frac{0.80 mol}{2 L}=0.40 mol/L

The formation constant of the complex = K_f=4.0\times 10^{18}

The expression of formation constant is given as:

K_f=\frac{[[Ni(en)_3]^{2+}]}{[Ni^{2+}][en]^3}

4.0\times 10^{18}=\frac{0.08 mol/L}{x\times (0.40 mol/L)^3}

x=\frac{0.08 mol/L}{4.0\times 10^{18}\times (0.40 mol/L)^3}

x=3.125\times 10^{-19} mol/L

3.125\times 10^{-19} mol/L is the concentration of Ni^{2+}(aq) in the solution.

6 0
3 years ago
When 150. g zinc sulfide are burned in excess oxygen, 68.5 g of zinc oxide are actually produced, along with sulfur dioxide. Det
Bumek [7]

%yield = 54.6%

<h3>Further explanation</h3>

Percent yield is the compare of the amount of product obtained from a reaction with the amount you calculated

(theoretical)

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

<h3 />

Reaction

2ZnS+3O₂ ⇒ 2ZnO+2SO₂

MW ZnS = 97.474 g/mol

  • mol ZnS

\tt \dfrac{150}{97.474}=1.54

MW ZnO = 81.38 g/mol

  • mol ZnO (from mol ZnS as limiting reactant, O₂ excess)

\tt \dfrac{2}{2}\times 1.54=1.54

  • Actual ZnO produced

\tt 1.54\times 81.38=125.33~g

Theoretical production = 125.388

  • %yield

\tt \dfrac{68.5}{125.33}\times 100\%=\boxed{\bold{54.6\%}}

4 0
3 years ago
Estimate the ligand fi eld splitting for (a) [CrCl6]3 (max 740 nm), (b) [Cr(NH3)6]3 (max 460 nm), and (c) [Cr(OH2)6]3 (max 575 n
igor_vitrenko [27]

Answer:

NH3>H2O>Cl-

Explanation:

The given wavelengths of maximum absorption for each complex can be used to estimate the magnitude of field splitting of the respective ligands as shown in the image attached. The field splitting is reported in the unit kilojoule per mole (KJmol-1).

It can be seen from the calculation in the image attached that ammonia shows the highest crystal field splitting followed by water and lastly the chloride anion. This corresponds to the respective positions of these species in the spectrochemical series. Water and the chloride ion are weak field ligands.

4 0
3 years ago
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