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amid [387]
3 years ago
10

A star is observed from two positions of Earth in its orbit, in summer and winter. Which of these is the best method to calculat

e the approximate distance of the star from Earth? measure the parallax and use it in calculations measure the red shift of emitted light and use it in calculations use doppler effect to calculate the shift in light traveling from star to Earth in winter use doppler effect to calculate the shift in light traveling from star to Earth in summer
Chemistry
1 answer:
Fantom [35]3 years ago
6 0

Answer:

D. Calculate the variations in the potions of the star due to movement of Earth in its orbit

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Frequency of 6.98 x 1013
MAVERICK [17]

Answer:7,070.74

Explanation:because frequency has a lot of energy

6 0
3 years ago
Match the chemical Equation with his correct type
Alex

Answer:

The answer to your question is given below

Explanation:

1. C. 2NaCl + I2 —> 2NaI + Cl2 => C. Single displacement.

From the above equation, we can see that I2 replaces Cl in NaCl to produce NaI. This is simply called a single displacement reaction.

2. E. 2C4H10 + 13O2 —> 8CO2 + 10H2O => E. Combustion.

The above equation shows the burning of Hydrocarbon in the presence of O2. This is simply called Combustion as CO2 and H2O is produced.

3. D 2H2O —> 2H2 + O2 => D. Decomposition.

From the above equation, we can see that a single compound H2O produces two elements H2 and O2. This is simply called a decomposition reaction.

4. A. ZnS + 2HCl —> ZnCl2 + H2S => A. Double Decomposition.

From the above equation, we can see that Cl replaces S in ZnS to produce ZnCl2 and S replaces Cl in HCl to produce H2S. This is simply called double displacement reaction.

5. B. H2 + Br2 —> 2HBr => B. Synthesis.

From the above equation, we can see that two element H2 and Br2 combine to produce a single compound HBr. This is simply called a synthesis reaction.

7 0
3 years ago
What happens to the average kinetic energy of the particles in a sample of matter as the temperature of the sample is increased?
antiseptic1488 [7]

Answer:

  • <em>As the temperature of a sample of matter is increased, the average kinetic energy of the particles in the sample </em><u>increase</u><em>.</em>

Explanation:

The <em>temperature</em> of a substance is the measure of the <em>average kinetic energy </em>of its partilces.

The temperature, i.e. how hot or cold is a substance, is the result of the collisions of the particles (atoms or molecules) of matter.

The kinetic theory of gases states that, if the temperature is the same, the average kinetic energy of any gas is the same, regardless the gas and other conditions.

This equation expresses it:

  • Avg KE = (3/2) (R / N) T

Where Avg KE is the average kinetic energy, R is the universal constant of gases, N is Avogadro's constnat, and T is the temperature measure in absolute scale (Kelvin).

As you see, in that equation Avg KE is propotional to T, which means that as the temperature is increased, the average kinetic energy increases.

7 0
3 years ago
What is the summary at the end of an experiment that explains the results
jasenka [17]

Answer:

The conclusion

Explanation:

6 0
3 years ago
An aqueous CsCl solution is 8.00 wt% CsCl and has a density of 1.0643 g/mL at 20°C. What is the boiling point of this solution?
umka2103 [35]

<u>Answer:</u> The boiling point of solution is 100.53

<u>Explanation:</u>

We are given:

8.00 wt % of CsCl

This means that 8.00 grams of CsCl is present in 100 grams of solution

Mass of solvent = (100 - 8) g = 92 grams

The equation used to calculate elevation in boiling point follows:

\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=iK_bm

Or,

\text{Boiling point of solution}-\text{Boiling point of pure solution}=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Boiling point of pure solution = 100°C

i = Vant hoff factor = 2 (For CsCl)

K_b = molal boiling point elevation constant = 0.51°C/m

m_{solute} = Given mass of solute (CsCl) = 8.00 g

M_{solute} = Molar mass of solute (CsCl) = 168.4  g/mol

W_{solvent} = Mass of solvent (water) = 92 g

Putting values in above equation, we get:

\text{Boiling point of solution}-100=2\times 0.51^oC/m\times \frac{8.00\times 1000}{168.4g/mol\times 92}\\\\\text{Boiling point of solution}=100.53^oC

Hence, the boiling point of solution is 100.53

6 0
3 years ago
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