Question

Jake is solving x^2-6x+5=0 by completing the square his steps are shown below step 1. x^2-6x=-5 step 2. x^-6x+9=-5+9 step 3. (x-6)^2=4 Step 4. sq root (x-6)^2=sq root 4 step 5. x-6=+- 2 step 6. x=6+-2 step 7. x=8 and x =4. which step is Jakes error in.

Answer 1

Answer:

Jake's error in step 3

Step-by-step explanation:

we have

$x^{2} -6x+5=0$

Complete the square

step 1

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2} -6x=-5$

step 2

Complete the square. Remember to balance the equation by adding the same constants to each side

$x^{2} -6x+9=-5+9$

$x^{2} -6x+9=4$

step 3

Rewrite as perfect squares

$(x-3)^{2}=4$

Jake's error in step 3

He placed 6 instead of 3 in the left side

step 4

take square root both sides

$\sqrt{(x-3)^2} =\sqrt{4}$

step 5

$(x-3)=\pm2$

step 6

$x=3\pm2$

step 7

x=5 and x=1