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lara31 [8.8K]
3 years ago
8

A ticket to Silver Dollar City costs $125. You have a coupon that will save you 33%. How much will you SAVE? In the same scenari

o, how much will you end up SPENDING for you ticket if you use your coupon?
Mathematics
1 answer:
vampirchik [111]3 years ago
7 0
You will save 41.25 dollars, and you will pay 83.75 dollars if you use the coupon.
To get the percent of money you save you multiply 125 dollars by 33% to get your answer. To get the number of dollars you will take the amount you got by multiplying 125 dollars by 33% and subtract it from 125, so that’s 125 - 41.25 = 83.75
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16.985 in word form?
Shkiper50 [21]
Sixteen point nine hundred eighty five

6 0
3 years ago
The interest rate on the marshals variable rate mortgage increased from 10% to 12%. Their old monthly payment was $437.24. their
kakasveta [241]

Step-by-step explanation:

the difference in monthly pymts $59. 49/mthly

$59.49 × 12 = $713.88 increase in pymts in 1 year.

8 0
3 years ago
What is the true solution to 3 in 2 + in 8 = 2 in (4x)
11Alexandr11 [23.1K]
The first step for solving this equation is to determine the defined range.
3㏑(2) + ㏑(8) = 2㏑(4x), x > 0
Write the number 8 in exponential form.
3㏑(2) + ㏑(2³) = 2㏑(4x)
Using ㏑(a^{x}) = x × ㏑(a),, transform the expression.
3㏑(2) + 3㏑(2) = 2㏑(4x)
Now collect the like terms on the left side of the equation.
6㏑(2) = 2㏑(4x)
Switch the sides of the equation.
2㏑(4x) = 6㏑(2)
Using x × ㏑(a) = ㏑(a^{x}),, transform the expression on the left side of the equation.
㏑((4x)²) = 6㏑(2)
Using x × ㏑(a) = ㏑(a^{x}),, transform the expression on the right side of the equation.
㏑((4x)²) = ㏑(2^{6})
Since the bases of the logarithms are the same,, you need to set the arguments equal.
(4x)² = 2^{6}
Take the square root of both sides of the equation and remember to use both the positive and negative roots.
4x = +/- 8
Now separate the equation into 2 possible cases.
4x = 8
4x = -8
Solve the top equation for x.
x = 2
Solve the bottom equation for x.
x = 2
         , x > 0
x = -2
Lastly,, check if the solution is in the defined range to find your final answer.
x = 2
This means that the correct answer to your question is x = 2.
Let me know if you have any further questions
:)
5 0
3 years ago
Read 2 more answers
Use the substitution method to solve.<br><br> y=5−3x<br> 5x−4y=−3
Vadim26 [7]
Well just substitute y (the first equation) into the second equation.
So
5x-4(5-3x)=-3
Then just solve the equation from there.
5x-20+12x=-3
17x=17
x=1
and if you need y, y=2
6 0
3 years ago
Suppose x=c1e−t+c2e3tx=c1e−t+c2e3t. Verify that x=c1e−t+c2e3tx=c1e−t+c2e3t is a solution to x′′−2x′−3x=0x′′−2x′−3x=0 by substitu
Harrizon [31]

The correct question is:

Suppose x = c1e^(-t) + c2e^(3t) a solution to x''- 2x - 3x = 0 by substituting it into the differential equation. (Enter the terms in the order given. Enter c1 as c1 and c2 as c2.)

Answer:

x = c1e^(-t) + c2e^(3t)

is a solution to the differential equation

x''- 2x' - 3x = 0

Step-by-step explanation:

We need to verify that

x = c1e^(-t) + c2e^(3t)

is a solution to the differential equation

x''- 2x' - 3x = 0

We differentiate

x = c1e^(-t) + c2e^(3t)

twice in succession, and substitute the values of x, x', and x'' into the differential equation

x''- 2x' - 3x = 0

and see if it is satisfied.

Let us do that.

x = c1e^(-t) + c2e^(3t)

x' = -c1e^(-t) + 3c2e^(3t)

x'' = c1e^(-t) + 9c2e^(3t)

Now,

x''- 2x' - 3x = [c1e^(-t) + 9c2e^(3t)] - 2[-c1e^(-t) + 3c2e^(3t)] - 3[c1e^(-t) + c2e^(3t)]

= (1 + 2 - 3)c1e^(-t) + (9 - 6 - 3)c2e^(3t)

= 0

Therefore, the differential equation is satisfied, and hence, x is a solution.

4 0
3 years ago
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