Question

If T is the point at the given distance on the unit circle C from P (1, 0), determine the quadrant in which T lies:

Answer 1

Hello,

Answer D

9π/6<11π/6<12π/6
Quadrant IV

Answer 2

Answer:

Option d) is correct

Step-by-step explanation:

T is a point at a given distance on the unit circle from P(0,1) .

Clearly, the point P(0,1) lies on the circle itself .

To find: the quadrant in which T lies

Given: angle at which point T lies is $\frac{11\pi}{6}$.

Solution :

$\frac{11\pi}{6}=\frac{11\times 180^{\circ}}{6}=11\times 30^{\circ}=330^{\circ}$

As $270^{\circ}< 330^{\circ}< 360^{\circ}$,

So, basically we are talking about the fourth quadrant as angle $330^{\circ}$ lies in the fourth quadrant .

Therefore, point T lies in quadrant IV.

i.e If T is the point at the given distance on the unit circle C from P (1, 0), then T lies in the IV quadrant.

So, option d) is correct .