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3 years ago

The sides of a square or three and 2/7inches long what is the area of a square

Mathematics

1 answer:

alisha [4.7K]3 years ago

5 0

A=lw

A= (3 2/7in)^2

A=10.8 inches squared

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Find the value of 4³

Gwar [14]

Answer:

Step-by-step explanation:

4^3 is the same as 4x4x4

4x4 = 16

16x4=64

so 4^3 is 64

4 0

1 year ago

Read 2 more answers

If you have 10 apples what where is the 9th one?

FromTheMoon [43]

To Your First Nine Friends, You Give Them 1 Apple Each. Your Tenth Friend, You Give Her The Basket With The Tenth Apple. She Has The Apple, And The Basket?

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4 years ago

Last year 63 inches of rain fell oaktown. In pine city 7 inches of rain fell last year. Write and solve equation to find how man

Nonamiya [84]

Answer:

Oaktown had 9 times more inches of rain than Pine City did.

Step-by-step explanation:

63 divided by 7 = 9.

Very simple problem. Glad to help.

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3 years ago

PROBLEM SOLVING When a plant or animal dies, it stops acquiring carbon-14 from the atmosphere. The amount y in grams) of carbon-

kykrilka [37]

Answer:

0.01%

Step-by-step explanation:

y=a (0.5)^t/5730

y=a [(0.5)^t/5730]

when you put 0.5^1/5730

it'll give you 0.99

The "equation" is y=a(1-r)^t

so 1-0.99 is 0.01

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3 years ago

B. Determine the values of a and b so that f is continuous.<br><br> Please help!

wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

$\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to 4a-2b+3 = 4\\\\ \therefore \ \ 4a-2b = 1\\\\$

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

$\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\$

So,

$\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3$

$\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\$

In equation a multiply the by -2 and then add in the equation b:

$\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to -2b = -1\\\\ \to b = \frac{1}{2}$

So, the value of $a \ and \ b= \frac{1}{2}$

4 0

3 years ago