A property map is drawn at a scale of 1:1000. Calculate the corresponding actual distance if the distance between two points on
the map is: 1 cm PLZ HELP ME
1 answer:
Answer:10 m
Step-by-step explanation:
Given
Scaling ratio 1:1000
i.e. one unit in map is equal to 1000 unit in actual distance
therefore if the distance between two points is 1 cm in map then
it is 1000 cm in reality
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<u>Step-by-step explanation:</u>
We have , 
,
We know that ![sin\alpha = \frac{Perpendicular}{Hypotenuse} = \frac{Perpendicular}{\sqrt[2]{(Perpendicualr)^{2} + (Base)^{2})} }](https://tex.z-dn.net/?f=sin%5Calpha%20%20%3D%20%5Cfrac%7BPerpendicular%7D%7BHypotenuse%7D%20%3D%20%5Cfrac%7BPerpendicular%7D%7B%5Csqrt%5B2%5D%7B%28Perpendicualr%29%5E%7B2%7D%20%2B%20%28Base%29%5E%7B2%7D%29%7D%20%7D)
Substituting values of P & B , 
Now , 
⇒
×
×2
⇒ 
⇒
⇒
⇒
Answer:
me bro i need points mark me
Answer:
Step-by-step explanation:
X×X/2+3X+C
Answer:
10000000000000009
OML that's a lot of apples lol.
Step-by-step explanation:
Hope this helps ;)
Answer: Y=3, X=5
Step-by-step explanation:
2(2y-1) + 3y=19
4y-2+ 3y=19
7y=21
Y=3
Plug in y in the second equals
X=2(3) -1
X=6-1
X=5
Hope this helps!
