The answer to this question is the first item in the choices which is "The teacher should use the mean for both Amo and Javier" when computing and comparing their grades. The mean is the average grade while the median is the center of the grade. It would be wrong to apply median in computing their grades and it would be also wrong when the use two different methods when computing and comparing their grades.
Answer:
vertical
Step-by-step explanation:
bdvdhdvdhdvdhdhdvdhbdbdd
V=(1/3)hpir^2
aprox
d=2r
d/2=r
d=24
r=24/2=12
V=2713
2713=(1/3)hpi(12^2)
2713=(1/3)hpi(144)
2713=48pih
divide both sides by 48
56.5208=hpi
aprox pi=3.14
divide both sides by 3.14
56.5208/3.14=h=18.0003
height=18cm
What is the 9th term of the geometric sequence 4, -20, 100, ...
<span>First term, a = 4 </span>
<span>common ratio, r = –20 / 4 = –5 </span>
<span>..... ..... ..... ..... = 100 / –20 = –5 </span>
<span>9th term = 4 ( –5 ) ^ ( 9 - 1 ) </span>
<span>..... ...... = 4 ( –5 ) ^ 8 </span>
<span>..... ...... = 4 ( 390,625 ) </span>
<span>..... ...... = 1,562,500 </span>