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sdas [7]
3 years ago
8

Find the quotient in their exponential form.

Mathematics
2 answers:
netineya [11]3 years ago
7 0

Answer:

It is 0.609663161

Step-by-step explanation:

Hope this helped have an amazing day!

vodomira [7]3 years ago
6 0

Answer:

0.609663161

Step-by-step explanation:

(8/27)power5 = 5.57533755

(2/3)power7= 9.14494717

then, u just devide... from what i know

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Answer:

1. 4x + 6

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Step-by-step explanation:

Remove the parenthesis for each one so everything's out in the open. Next, you group like terms. The numbers with variables on one side, and the other numbers on the other side. For example:

x + 3x - 2 + 8

Then, you combine like terms:

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That's mostly how you do each one.

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What can you do when the unit prices for two comparable items are listed using different units of measure? a. The secondary unit
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Step-by-step explanation:

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Which of the following is an equivalent equation obtained by completing the square of the expression below? x^2+6x−8=0 A (x+3)^2
valentina_108 [34]

Answer:

Solving the equation x^2+6x-8=0 by completing the square method we get \mathbf{(x+3)^2=17}

Option B is correct option.

Step-by-step explanation:

We need to solve the equation x^2+6x-8=0 by completing the square method.

For completing the square method: we need to follow: a^2+2ab+b^2=(a+b)^2

We are given:

x^2+6x-8=0

Solving by completing the square

x^2+2(x)(?)+(?)^2-8=0

We need to find ? in our case ? is 3 because 2*3= 6 and our middle term is 6x i,e 2(x)(3)=6x.

So, adding and subtracting (3)^2

x^2+2(x)(3)+(3)^2-8-(3)^2=0\\(x+3)^2-8-9=0\\(x+3)^2-17=0\\(x+3)^2=17

So, solving the equation x^2+6x-8=0 by completing the square method we get \mathbf{(x+3)^2=17}

Option B is correct option.

7 0
3 years ago
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