First we want to calculate at what height and at what time rocket stops ascending.
h' = 256 - 32t = 0
32t = 256
t = 8
h = 256*8 - 16*8^2
h = 1024
Now we want to find time at which it gets 200 feet that means our equation is:
200 = 256t - 16*t^2
-16*t^2 + 256t - 200 = 0
t1 = 0.82s
t2 = 15.17s
time t1 is when rocket is ascending and t2 when it is descending therefore answer is t2
So my step one would be to add the six over and get 3x squared -9x+6=0, then divide by 3 to get x squared-3x+2=0. The next step is seeing what two numbers multiply to 2 but also add to negative three. The two numbers are -1 and -2. So then you are going to make two equations, one being x-1=0 and the other being x-2=0. Solve both to get X=1 and X=2, check your answers in the original equation. Hope this helps!
1. 30/120
2. 30/100
Have a gold day:)
The answer will be 57 after you add 43 to both sides.
Hshshshshshshs /// G equals 34
