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irinina [24]
3 years ago
15

Which type of angle is ABC? help quick!

Mathematics
2 answers:
vovikov84 [41]3 years ago
8 0

Answer:

A right angle.

Step-by-step explanation:

65+25 =90

djverab [1.8K]3 years ago
6 0

25+65= 90°

<em>Answer:∠ABC is a vertical angle. </em>Because, vertical angles are 90°

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Please help me ASAP: Answer with : includes / not includes
Elodia [21]

Answer:

Step-by-step explanation:

The interval [4, ∞) all real numbers 4 and greater, whereas the interval (4,∞) not includes the endpoint 4.

3 0
3 years ago
Who's good at Fractions? Will give Brainlest to who answers.
Inga [223]
You need to add two mixed numerals.
One is positive and one is negative.
To add a positive number and a negative number, first take the absolute value of both, making them both positive. Then subtract the smaller absolute value from the larger absolute value. Finally, the sign of the answer is the same sign as the number that has the larger absolute value.

The numbers are -4 5/8 and 2 1/8

Take absolute values:
|-4 5/8| = 4 5/8
|2 1/8| = 2 1/8

Subtract the smaller absolute value from the larger absolute value.

4 5/8 - 2 1/8 = 2 4/8 = 2 1/2

The greater absolute value is 4 5/8.
Since the number with the larger absolute value was -4 5/8, a negative number, the answer is negative, -2 1/2

-4 5/8 + 2 1/8 = - 2 1/2
6 0
3 years ago
A triangle has side lengths of
Angelina_Jolie [31]

Answer:

3 is the right one

Step-by-step explanation:

Simple math you know

3 0
2 years ago
0.016 as a fraction in simplest form
puteri [66]
0.016 as a fraction is 16/1000 and in simplest form it is 2/125.

An easy way to figure out the fraction of a decimal is by the decimal places. As we can see, there are four numbers in our decimal (0.016). 

The first decimal place = ones 
The second decimal place = tenths
The third decimal place = hundredths 
The fourth decimal place = thousandths

We stop at the thousandths place, so basically, take 16 and put it over 1000, which looks like 16/1000.

6 0
3 years ago
Read 2 more answers
−2x=x^2−6
Iteru [2.4K]

Step-by-step explanation:

Example 1

Solve the equation x3 − 3x2 – 2x + 4 = 0

We put the numbers that are factors of 4 into the equation to see if any of them are correct.

f(1) = 13 − 3×12 – 2×1 + 4 = 0 1 is a solution

f(−1) = (−1)3 − 3×(−1)2 – 2×(−1) + 4 = 2

f(2) = 23 − 3×22 – 2×2 + 4 = −4

f(−2) = (−2)3 − 3×(−2)2 – 2×(−2) + 4 = −12

f(4) = 43 − 3×42 – 2×4 + 4 = 12

f(−4) = (−4)3 − 3×(−4)2 – 2×(−4) + 4 = −100

The only integer solution is x = 1. When we have found one solution we don’t really need to test any other numbers because we can now solve the equation by dividing by (x − 1) and trying to solve the quadratic we get from the division.

Now we can factorise our expression as follows:

x3 − 3x2 – 2x + 4 = (x − 1)(x2 − 2x − 4) = 0

It now remains for us to solve the quadratic equation.

x2 − 2x − 4 = 0

We use the formula for quadratics with a = 1, b = −2 and c = −4.

We have now found all three solutions of the equation x3 − 3x2 – 2x + 4 = 0. They are: eftirfarandi:

x = 1

x = 1 + Ö5

x = 1 − Ö5

Example 2

We can easily use the same method to solve a fourth degree equation or equations of a still higher degree. Solve the equation f(x) = x4 − x3 − 5x2 + 3x + 2 = 0.

First we find the integer factors of the constant term, 2. The integer factors of 2 are ±1 and ±2.

f(1) = 14 − 13 − 5×12 + 3×1 + 2 = 0 1 is a solution

f(−1) = (−1)4 − (−1)3 − 5×(−1)2 + 3×(−1) + 2 = −4

f(2) = 24 − 23 − 5×22 + 3×2 + 2 = −4

f(−2) = (−2)4 − (−2)3 − 5×(−2)2 + 3×(−2) + 2 = 0 we have found a second solution.

The two solutions we have found 1 and −2 mean that we can divide by x − 1 and x + 2 and there will be no remainder. We’ll do this in two steps.

First divide by x + 2

Now divide the resulting cubic factor by x − 1.

We have now factorised

f(x) = x4 − x3 − 5x2 + 3x + 2 into

f(x) = (x + 2)(x − 1)(x2 − 2x − 1) and it only remains to solve the quadratic equation

x2 − 2x − 1 = 0. We use the formula with a = 1, b = −2 and c = −1.

Now we have found a total of four solutions. They are:

x = 1

x = −2

x = 1 +

x = 1 −

Sometimes we can solve a third degree equation by bracketing the terms two by two and finding a factor that they have in common.

6 0
3 years ago
Read 2 more answers
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