If you have a picture of the problem I can answer it so just send a pic of the math problem
The answer is 28 years
At = A0 * e^(-k * t)
At = 12 g
A0 = 15 g
k = 7.9 × 10^-3 = 0.0079
t = ?
12 = 15 * e^(-0.0079 * t)
12/15 = e^(-0.0079 * t)
0.8 = e^(-0.0079 * t)
Logarithm both sides (because ln(e) = 1:
ln(0.8) = ln(e^(-0.0079 * t))
ln(0.8) = (-0.0079 * t) * ln(e)
-0.223 = -0.0079 * t
t = -0.223 / -0.0079
t = 28.23
t ≈ 28 years
The answr is 2 okay that’s the answer
Answer:
5q I would say
Step-by-step explanation:
As
3
x
−
q
=
5
q
, adding
=
q
on both sides, we get
3
x
−
q
+
q
=
5
q
+
q
or
3
x
=
6
q
, now multiplying both sides by
1
3
, we get
3
x
×
1
3
=
2
6
q
×
1
3
or
x
=
2
q
Answer: 9
Step-by-step explanation: Here, we have the expression <em>4x - 7</em> and we want to evaluate the expression when <em>x</em> is equal to 4.
To evaluate an expression, we simply plug the value
of the variable into the expression and solve.
So here, since <em>x</em> is equal to 4, we have 4(4) - 7.
4(4) is equal to 16.
So we have 16 - 7 which is equal to 9.
So the value of our expression when <em>x</em> is equal to 4 is 9.
