What is the equation of the line that passes through the points (2, -4) and (0, 8)?
1 answer:
Answer:
C
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y-intercept )
To calculate m use the gradient formula
m = ( y₂ - y₁ ) / ( x₂ - x₁ )
with (x₁, y₁ ) = (2, - 4) and (x₂, y₂ ) = (0, 8)
m = =
= - 6
note the line passes through the point (0, 8) ⇒ c = 8
y = - 6x + 8 → C
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Answer:
x= 32.3 (3 s.f.)
θ= 21.8° (1 d.p.)
α= 68.2° (1 d.p.)
Step-by-step explanation:
Applying Pythagoras' Theorem,
x²= 12² +30²
x²= 144 +900
x²= 1044
Square root both sides:
x= 32.3 (3s.f.)
θ= 21.801° (3 d.p.)
θ= 21.8° (1 d.p.)
= 68.2° (1 d.p.)
Alternatively,
α +θ +90°= 180° (∠ sum of triangle)
α +21.801° +90°= 180°
α +111.801°= 180°
α= 180° -111.801°
α= 68.199°
α= 68.2° (1 d.p.)
