Question

write an equation of a line that passed through the point (2,0) and is a perpendicular to the line y=-1.5+3

Answer 1

You will be using the equation y = mx + b

The only variables you need to find are "m" and "b"

For the equation of a line to be perpendicular to the given line, the slope will have to be the opposite of the given slope. Or you have to flip the sign and the number of the given slope to get your new slope.

For example:

m = -2

perpendicular slope = 1/2(positive)

m = 3/4

perpendicular slope = -4/3(negative)

The slope of the line is -1.5 or -3/2

Your new slope is 2/3

y = 2/3x + b

To find "b", you plug in the point (2,0) into the equation.

0 = 2/3(2) + b

0 = 4/3 + b

-4/3 = b

Your new equation is y = 2/3x - 4/3