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2 years ago

Mean Versus Median

Mathematics

1 answer:

Lina20 [59]2 years ago

4 0

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data:

$1.09 $1.29 $1.29 $1.35 $1.39 $1.49 $1.59 $1.79

Average value :

Sarah = $1.37

Andrew = $1.41

Obtaining the median:

(n + 1) / 2

n = number of observations = 8

(8 + 1) / 2 = 9 /2 = 4.5th observation

(4th +. 5th observations) / 2

(1.35 + 1.39) / 2 = $1.37

Finding the mean:

($1.09 + $1.29 + $1.29 + $1.35 + $1.39 + $1.49 + $1.59 + $1.79) /8

$11.28 / 8

= $1.41

Hence, the actual. Average value is the mean value of the data.

The median only gives the value at the middle of the distribution and not the average.

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N76 [4]

Answer:

Step-by-step explanation:

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2 years ago

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2 years ago

Categorize these samples as representative or not representative of the given populations.

yuradex [85]

Representatives: This means that a certain amount of people would constitute what the majority would think too.

1) Tina interviews the school's soccer team about the exercise habits of the students at her school. (implying all the students). This means that Tina only goes to the soccer team instead of the whole school to find out the whole school's exercise habit.
2) Alana also counts as representatives, because she did not interview ALL of the teachers, rather just a selected majority (in this case)
5) For Jeremy, he only interviews 5 students from each class rather than all students
Not Representatives: Each person is given a choice of opinion and does not affect other people.
3) Joe talks to fathers of high school students, which could be larger than just 'representatives', and implies a larger group of people, and is not as selective as having representatives
4) Social Media constitutes of a large group of people, generally larger than a school, and if people take time to take the survey, it will generate a larger test-group. Also, everybody answering the survey would take time to think about themselves, and only represent themselves, and not others.

hope this helps

5 0

3 years ago

I need help with problems #1-3

Oksi-84 [34.3K]

<h3>Answer:</h3>

see below

<h3>Step-by-step explanation:</h3>

In general, there are five ways to find if two triangles are congruent: SSS, SAS, ASA, AAS and HL.

SSA is another way that can be used if (and only if) the measure of the angle is 90° or is known to be the largest angle in the triangle. (That's another way of saying the first S in SSA must be the longest side.)

HL is a special case of SSA in which the angle is exactly 90°.

(1)

ΔMXD ≅ ΔMYT . . . . by SAS congruence. Note the marks on the sides and the angle and the relationship between the angle and the sides—the angle is between the sides (SAS)
ΔBNG (not congruent) ΔBXY . . . . this would require congruence by SSA, as the angle is not between the sides marked congruent. It appears that NG and XY are the longest sides. If that appearance can be taken at face value, then the conditions for use of SSA congruence are met and the triangles can be declared congruent. (Usually, the appearance of a figure cannot be assumed to mean anything. The only thing that matters is the markings.)
ΔMPD (not congruent to anything) . . . . the marked angle on one side is not in the same relation to the marked side as it is on the other side of M.
ΔNMT (not congruent) ΔTCN . . . . this would require congruence by SSA as the alternate interior angles ∠MNT and ∠CTN are not between side TN and the other sides marked congruent. The angles at M and C appear to be right angles, but are not marked as such, so we cannot conclude that HL congruence can be shown. The congruent angles are not opposite the longest side (TN), so the conditions for SSA congruence are not met.
ΔITR ≅ ΔERT . . . . the relationship between the angles marked congruent and the common side (congruent to itself) TR is that of Angle, Angle, Side, so AAS congruence can be used.

___

(2) See above for a list of congruence theorems. AAA can be used to show similarity, but not congruence.

___

(3) See the discussion above. Only under certain circumstances can SSA be used as a "congruence shortcut." The 2nd and 4th examples above are partial illustration of this.

In the 4th example of problem (1), if the left and right parallel lines were skewed slightly more so that points C and M were closer together, it is easier to see that the line NC could be rotated about point N to a position where it would intersect line TC in a different place. Thus, even though the sides and angles are the same, there is no necessary congruence. (The attachment illustrates this.)

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2 years ago

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emmasim [6.3K]

Answer:

4599

Step-by-step explanation:

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2 years ago

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