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3 years ago

Round 593 to nearest ten Also are you in 2nd grade cause I am in 3rd

Mathematics

2 answers:

Tanzania [10]3 years ago

5 0

Answer:

590

Step-by-step explanation:

To the ten that is nearest to 593

gladu [14]3 years ago

5 0

Answer:

590

Step-by-step explanation:

Because your ones place is not higher than 5 the tens place stays the same and everything before becomes zero

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Taylor baked a cake to serve after dinner. Suppose she cut the cake into 8 equal size pieces and 6 people ate all the pieces.exp

REY [17]

All you need to do is 8 divided by 6. When you do so you get: 1.3 which could also be written as 1 3/8.

So each person gets 1 whole piece and 3/8 of another piece.

8 0

3 years ago

Dave buys a baseball catchers equipment for $295. The tax rate is 7.9%. How much tax did Dave pay? Round your answer to the near

Liono4ka [1.6K]

Answer:

23.31

Step-by-step explanation:

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2 years ago

In 2000 South Dakota had a population of 754,844. The number of people in South Dakota increased by 7.9% in 2010. What is South

Novay_Z [31]

814,180. Hope I helped. If i didn't I am sos sorry. I would take 7.9 or .079 to 754,844 to get your number.

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2 years ago

Please help me!!!!!!!!

strojnjashka [21]

Answer:

10) 1/11

11) 18/8 or 2 2/8 or 2 1/4

12) -8/5 or -1 3/5

Step-by-step explanation:

10) -6/11-(-5/11)=-6/11+(5/11)=<em>1/11</em>

11) 1 3/8-(-7/8)=11/8+7/8=18/8 or 2 2/8 or 2 1/4

12) -4/5-4/5=-8/5 or -1 3/5

4 0

2 years ago

Use the distance formula to determine the distance between (-8,10) and (-6,7)

hjlf

Answer:

Distance: $\sqrt{13}$ units

Step-by-step explanation:

The distance formula is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ where:

$d$ is the distance between points $(x_1,y_1)$ and $(x_2,y_2)$
$(x_1,y_1)$ are the coordinates of the first point
$(x_2,y_2)$ are the coordinates of the second point

We are given that:

$(x_1,y_1)=(-8,10)$
$(x_2,y_2)=(-6,7)$

To determine the value of our distance, $d$ , we plug in our given information into the formula and solve for

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$d=\sqrt{(-6-(-8))^2+(7-10)^2}$

$d=\sqrt{(-6+8)^2+(-3)^2}$

$d=\sqrt{(2)^2+(-3)^2}$

$d=\sqrt{4+9}$

$d=\sqrt{13}$

Therefore, the distance between $(-8,10)$ and $(-6,7)$ is $\sqrt{13}$ units.

See the attached graph for a visual.

5 0

2 years ago