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Sergeu [11.5K]
3 years ago
5

I have a water tank that holds 5 gallons of water I drink 4 pints of water a day how many full tanks of water I will be drinking

30 days
Mathematics
1 answer:
julsineya [31]3 years ago
4 0


                             gfdddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd

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When you spend $1 at the grocery store, the store doesn’t keep all of your money as profit. Some of it is reinvested in the econ
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The total economic impact of the factory’s initial investment is the sum of all the investments and reinvestments over the months.
Part D: What is the total economic impact after the first four months?
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The complex zeros of the following polynomial function. Write f in factored form.
zavuch27 [327]

Answer:  \bold{x=-3\qquad x=\dfrac{3+3i\sqrt3}{2}\qquad x=\dfrac{3-3i\sqrt3}{2}}

<u>Step-by-step explanation:</u>

The formula for factoring a cubic is:

a³ + b³ = (a + b)(a² - ab + b²)

f(x) = x³ + 3³

     = (x + 3)(x² - 3x + 9)

To find the zeros, set each factor equal to zero and solve.

0 = x + 3      0 = x² - 3x + 9

-3 = x                use quadratic formula

x^2-3x+9\quad \rightarrow \quad a=1, b=-3, c=9\\\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(-3)\pm\sqrt{(-3)^2-4(1)(9)}}{2(1)}\\\\\\x=\dfrac{3\pm\sqrt{9-36}}{2}\\\\\\x=\dfrac{3\pm\sqrt{-27}}{2}\\\\\\x=\dfrac{3\pm3i\sqrt{3}}{2}

Answer:

x=-3\qquad x=\dfrac{3+3i\sqrt3}{2}\qquad x=\dfrac{3-3i\sqrt3}{2}

7 0
3 years ago
Definition: This is a decimal number which never ends, but whose digits after the decimal point come in a predictable pattern. E
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Answer:

 the answer is repeating

Step-by-step explanation:

I hope this helps you :)

7 0
3 years ago
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Spiral Review Overnight, the temperature decreased by 17 1/2 °F. If the temperature began at -3.6 °F, what is the current temper
Alex

Answer: -21.1°F

Step-by-step explanation:

-3.6 - 17.5 = -21.1°F

7 0
3 years ago
Let 0 be an acute angle of a right triangle. Evaluate the other five trigonometric functions of 0.
Ainat [17]

Answer:

1. Cos θ = 6√2 / 11

2. Tan θ = 7 / 6√2

3. Cosec θ = 11 / 7

4. Sec θ = 11 / 6√2

5. Cot θ = 6√2 / 7

Step-by-step explanation:

From the question given above, the following data were obtained:

Sine θ = 7 / 11

Next, we shall determine the adjacent of the right triangle. This can be obtained as follow:

Sine θ = 7 / 11

Sine θ = Opposite / Hypothenus

Opp = 7

Hypo = 11

Adj =?

Hypo² = Opp² + Adj²

11² = 7² + Adj²

121 = 49 + Adj²

Collect like terms

Adj² = 121 – 49

Adj² = 72

Take the square root of both side

Adj = √72

Adjacent = 6√2

1. Determination of Cos θ

Adjacent = 6√2

Hypothenus = 11

Cos θ =?

Cos θ = Adjacent / Hypothenus

Cos θ = 6√2 / 11

2. Determination of Tan θ

Opposite = 7

Adjacent = 6√2

Tan θ =?

Tan θ = Opposite / Adjacent

Tan θ = 7 / 6√2

3. Determination of Cosec θ

Sine θ = 7 / 11

Cosec θ =?

Cosec θ = 1 ÷ Sine θ

Cosec θ = 1 ÷ 7 / 11

Cosec θ = 1 × 11/7

Cosec θ = 11/7

4. Determination of Sec θ

Cos θ = 6√2 / 11

Sec θ =?

Sec θ = 1 ÷ Cos θ

Sec θ = 1 ÷ 6√2 / 11

Sec θ = 1 × 11 / 6√2

Sec θ = 11 / 6√2

5. Determination of Cot θ

Tan θ = 7 / 6√2

Cot θ =?

Cot θ = 1 ÷ Tan θ

Cot θ = 1 ÷ 7 / 6√2

Cot θ = 1 × 6√2 / 7

Cot θ = 6√2 / 7

7 0
3 years ago
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