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3 years ago

Which are characteristics of carbon? Check all that apply.

Chemistry

2 answers:

user100 [1]3 years ago

6 0

Explanation:

Carbon is a non-metal that belongs to group 14. Atomic number of carbon is 6 and its electronic distribution is 2, 4.

So, in order to complete its octet it always shares its valence electrons with other atoms. Therefore, a carbon atom always leads to the formation of covalent compounds through covalent bonding.

A covalent bonding is the bonding occurring due to sharing of electrons between the combining atoms.

Being a non-metal and since it forms covalent bonds only, carbon is non-polar in nature. Hence, generally it is present in non-electrolytes. Also, it is insoluble in water (polar solvent).

It has low melting point and due to its ability of sharing valence electrons it forms a variety of compounds.

Thus, we can conclude that characteristics of carbon are as follows.

1. covalent bonding

3. generally in non-electrolytes .

4. low melting point

6. forms a variety of compounds

AveGali [126]3 years ago

3 0

Answer:

1,3,4,6

Explanation:

just got it right :) brainliest???

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Lina20 [59]

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Hydrogen Fluoride / HF

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3 0

3 years ago

A substance with a high [H+ ] would likely have which additional characteristics?

IRISSAK [1]

Answer:

low pH

Explanation:

Since pH = -log [H+], a high [H+] would mean that the pH is low.

4 0

3 years ago

True or False: The particles in the GASEOUS state are the furthest apart

tatyana61 [14]

The answer is true, particles in the gaseous state are the furthest apart

4 0

3 years ago

Consider the decomposition of red mercury(II) oxide under standard state conditions. )H0 T SFE ڮ( H M 0 H (a) Is the decompositi

sertanlavr [38]

The question is incomplete, complete question is :

Consider the decomposition of red mercury(II) oxide under standard state conditions.

$2HgO(s)\rightarrow 2Hg(l)+O_2(g)$

Given :

$\Delta S_{HgO}^o=70.29 J/mol K$

$\Delta S_{Hg}^o=75.9 J/mol K$

$\Delta S_{O_2}^o=205.2 J/mol K$

Enthalpy change of the reaction = ΔH = -90.83 kJ/mol

(a) Is the decomposition spontaneous under standard state conditions?

(b) Above what temperature does the reaction become spontaneous?

Answer:

a) The decomposition is spontaneous under standard state conditions.

b)The reaction will spontaneous above -419.69 Kelvins.

Explanation:

$2HgO(s)\rightarrow 2Hg(l)+O_2(g)$

Given :

$\Delta S_{HgO}^o=70.29 J/mol K$

$\Delta S_{Hg}^o=75.9 J/mol K$

$\Delta S_{O_2}^o=205.2 J/mol K$

Entropy change of the reaction ; ΔS

$\Delta S=[2\times \Delta S_{Hg}^o+1\times \Delta S_{O_2}^o]-[2\times \Delta S_{HgO}^o]$

$=[2\times 75.9 J/mol K+1\times 205.2 J/molK]-[2\times 70.29 J/molK]=216.42 J/mol K$

Enthalpy change of the reaction = ΔH = -90.83 kJ/mol = -90830 J/mol K

1 kJ = 1000 J

At standard condition the value of temperature = T = 298 K

ΔG = ΔH - TΔS

ΔG = -90830 J/mol K - 298 K × 216.42 J/mol K = -155,323.16 J/mol

ΔG < 0 ( spontaneous)

The decomposition is spontaneous under standard state conditions.

b) Above what temperature does the reaction become spontaneous

Let the ΔG = 0

Enthalpy change of the reaction = ΔH = -90.83 kJ/mol = -90830 J/mol K

ΔG = ΔH - TΔS

0 = -90830 J/mol K - T × 216.42 J/mol K

T = -419.69 K

The reaction will spontaneous above -419.69 Kelvins.

6 0

3 years ago

Use IUPAC rules to name this compound. A) nitrogen iodide B) nitrogen triiodide C) mononitrogen iodide D) mononitrogen triiodide

Mariulka [41]

Answer:

Name of the compound is Nitrogen triiodide.

Explanation:

According to the IUPAC rules, to naming of the compound the following formula can be applied.

Prefix + Name of first element + Base name element of second element + Suffix.

The given compound - $NI_{3}$

Name of first element- Nitrogen

Base name element of second element - Iodine

Suffix = 3 = tri

Here, iodine is in ionic form therefore, it becomes iodide. and then suffix will be added in front of the halogen.

Therefore, name of the compound will be Nitrogen triiodide..

3 0

3 years ago

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