Synthesis, decomposition, single replacement and double replacement.
Synthesis- two or more reactants unite to form a single product
S (Sulfur) + O2 (Oxygen) ——> SO2 (Sulphur dioxide)
Decomposition- A single reactant is decomposed or broken down into two or more
CaCO3 (Calcium Carbonate) ——> CaO (Calcium oxide) + CO2 (Carbon dioxide)
Single replacement- A single free element replaces or is substituted for one of the elements in a compound. The free element is more reactive than the one its replaces.
Zn (Zinc) + 2 HCI (hydrochloric acid) ——> H2 (hydrogen) + ZnCl2 (Zinc Chloride)
Double replacement- This reaction type can be viewed as an "exchange of partners." For ionic compounds, the positive ion in the first compound combines with the negative ion in the second compound, and the positive ion in the second compound combines with the negative ion in the first compound.
HCI (hydrochloric acid) + NaOH (sodium hydroxide) ——> NaCl (Sodium Chloride) + HOH (water)
Once reactants have absorbed enough heat energy from their surroundings to reach the transition state, the reaction will proceed. The activation energy of a particular reaction determines the rate at which it will proceed. The higher the activation energy, the slower the chemical reaction will be.
V1/T1 = V2/T2
Substitute the value use ratio and proportion. Use calculator.
V1 = (V2 x T1) / T2
1 is initial, 2 is final
This problem is providing us with the molality of a solution of calcium iodide as 0.01 m. So the most likely van't Hoff factor is required and theoretically found to be 3 due to the following:
<h3>Van't Hoff factor:</h3>
In chemistry, the correct characterization of solutions also imply the identification of the ions it will release in aqueous solution. For that reason, the van't Hoff factor gives us an idea of this number, according to the formula the solute has got.
In such a way, for calcium iodide, we write its ionization equation as shown below:
Assuming it is able to ionize due to the low molality, because if it was higher, then it won't ionize. Hence, since we have three moles of ion products, one Ca²⁺ and two I⁻, we can conclude the van't Hoff factor would be 3, although calculations may lead to a different, yet close result.
Learn more about the van't Hoff factor: brainly.com/question/23764376
Answer:
by the expirement:
In which mix salt with water
Answer:
7.64 Moles
Explanation:
As we know one mole of any substance contains 6.022 × 10²³ particles (atoms, ions, molecules or formula units). This number is also called as Avogadro's Number.
The relation between Moles, Number of Particles and Avogadro's Number is given as,
Number of Moles = Number of Particles ÷ 6.022 × 10²³
Putting values,
Number of Moles = 4.60 × 10²⁴ Particles ÷ 6.022 × 10²³
Number of Moles = 7.64 Moles