Answer:
True, based on the <em>Transitive Property of Equality</em>.
Step-by-step explanation:
Note that the <em>Transitive Property of Equality </em>states that "If a = b, & b = c, then a = c.
In this case it is the same.
∠1 ≅ ∠2 (because both are complementary), ∠1 ≅ ∠3 (again, both are complementary), then based on the Transitive Property, ∠2 ≅ ∠3, making all of them complementary angles
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<em>~Senpai</em>
The area of the rhombus and trapezoid from the figure are 2 square in and 5 square in respectively
<h3>How to find the area of a trapezoid and rhombus?</h3>
The given pattern consists of rhombus and trapezoids
The formula for calculating the area of rhombus is expressed as:
A = pq/2
Area of trapezoid = 0.5(a+b)h
Given the following
height = 2in
a = 2in
b = 3in
Ara of rhombus = 1(4)/2 = 2 square inches
Area of the trapezoid = 0.5(2+3) * 2
Area of the trapezoid = 5 square inches
Hence the area of the rhombus and trapezoid from the figure are 2 square in and 5 square in respectively
Learn more on area of rhombus and trapezoid here: brainly.com/question/2456096
Answer:
Step-by-step explanation:
y = x - 1/4
x = 1/4 Put this value in for x
y = 1/4 - 1/4
y = 0
x = 13/4
y = 13/4 - 1/4 The denominators remain the same The numerators are subtracted.
y = (13 - 1)/4
y = 12/4
y = 3
If x is to = 2 then it must be changed so it's denominator is 4
2 = 8/4
y= 8/4 - 1/4
y = 7/4 or 1.75 or 1 3/4
Answer:
I think its - 2/3
Step-by-step explanation:
Answer:
9
Step-by-step explanation:
![4a+7\\\\a=\frac{1}{2}\\\\=4[\frac{1}{2}]+7\\\\=2+7\\\\=9](https://tex.z-dn.net/?f=4a%2B7%5C%5C%5C%5Ca%3D%5Cfrac%7B1%7D%7B2%7D%5C%5C%5C%5C%3D4%5B%5Cfrac%7B1%7D%7B2%7D%5D%2B7%5C%5C%5C%5C%3D2%2B7%5C%5C%5C%5C%3D9)
