Answer:
10/18 and 20/36
Step-by-step explanation:
V = lwh
V = (x + 2)(x + 3)(x)
V = (x)(x^2 + 3x + 2x + 6)
V = (x^3 + 3x^2 + 2x^2 + 6x)
V = x^3 + 5x^2 + 6x
All you do is foil the dimensions together and then combine like terms. Hope this helps!
9514 1404 393
Answer:
y -2 = -2/3(x +4)
Step-by-step explanation:
There are several different forms of the equation for a line. Each is useful in its own way. Here, the line crosses the y-axis at a point between integer values, so using that intercept point could be problematical. That suggests the "point-slope" form of the equation for a line would be a better choice.
That form is ...
y -k = m(x -h) . . . . . . . line with slope m through point (h, k)
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The two marked points are (-4, 2) and (5, -4). All we need is the slope.
The slope is given by the formula ...
m = (y2 -y1)/(x2 -x1) . . . . . . . . where the given points are (x1, y1) and (x2, y2)
m = (-4 -2)/(5 -(-4)) = -6/9 = -2/3
Using the first point, the equation for the line can now be written as ...
y -2 = -2/3(x -(-4))
y -2 = -2/3(x +4)
Answer:
y=0
Step-by-step explanation:
Hello!
To solve this problem and find the asymptote you must find the value of x, for which F (x) (or y) becomes infinite, for this we solve the equation for X
As you can see if Y takes a value of zero, then X would tend to be an infinitely large value so we conclude the horizontal asymptote is y = 0, I also attached the graph!
