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Sever21 [200]
3 years ago
15

Which is an equation of a line , in point-slope form,that passes through (1,-7)and has a slope of -2/3

Mathematics
1 answer:
padilas [110]3 years ago
5 0

The answer is y-7=-2/3(x+1)


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Not sure if any of this is correct, but it’s what I got so far
Irina18 [472]

Problem 1 is correct. You use the pythagorean theorem to find the hypotenuse.

==================================================

Problem 2 has the correct answer, but one part of the steps is a bit strange. I agree with the 132 ft/sec portion; however, I'm not sure why you wrote \frac{1 \text{ sec}}{132 \text{ ft}}=\frac{0.59\overline{09}}{78 \text{ ft}}*127 \text{ ft}

I would write it as \frac{1\text{ sec}}{132 \text{ ft}}*127 \text{ ft} = \frac{127}{132} \text{ sec} \approx 0.96 \text{ sec}

==================================================

For problem 3, we first need to convert the runner's speed from mph to feet per second.

17.5 \text{ mph} = \frac{17.5 \text{ mi}}{1 \text{ hr}}*\frac{1 \text{ hr}}{60 \text{ min}}*\frac{1 \text{ min}}{60 \text{ sec}}*\frac{5280 \text{ ft}}{1 \text{ mi}} \approx 25.667 \text{ ft per sec}

Since the runner needs to travel 90-12 = 78 ft, this means\text{time} = \frac{\text{distance}}{\text{speed}} \approx \frac{78 \text{ ft}}{25.667 \text{ ft per sec}} \approx 3.039 \text{ sec}

So the runner needs about 3.039 seconds. In problem 2, you calculated that it takes about 0.96 seconds for the ball to go from home to second base. The runner will not beat the throw. The ball gets where it needs to go well before the runner arrives there too.

-------------

The question is now: how much of a lead does the runner need in order to beat the throw?

Well the runner needs to get to second base in under 0.96 seconds.

Let's calculate the distance based on that, and based on the speed we calculated earlier above.

\text{distance} = \text{rate}*\text{time} \approx (25.667 \text{ ft per sec})*(0.96 \text{ sec}) \approx 24.64032 \text{ ft}

This is the distance the runner can travel if the runner only has 0.96 seconds. So the lead needed is 90-24.64032 = 65.35968 feet

This is probably not reasonable considering it's well over halfway (because 65.35968/90 = 0.726 = 72.6%). If the runner is leading over halfway, then the runner is probably already in the running motion and not being stationary.

As you can see, the runner is very unlikely to steal second base. Though of course such events do happen in real life. What may explain this is the reaction time of the catcher may add on just enough time for the runner to steal second base. For this problem however, we aren't considering the reaction time. Also, not all catchers can throw the ball at 90 mph which is quite fast. According to quick research, the MLB says the average catcher speed is about 81.8 mph. This slower throwing speed may account for why stealing second base isn't literally impossible, although it's still fairly difficult.

5 0
2 years ago
13 mm<br> 17 mm<br> What would the area of the triangle
Bad White [126]

Answer:

110.5mm

Step-by-step explanation:

Formula : a = hb/2

a = 13(17)/2

221/2 = 110.5

5 0
3 years ago
Find the angle in degrees
BlackZzzverrR [31]

Answer:

90 degrees

Step-by-step explanation:

its a 45-45-90 triangle

3 0
2 years ago
Erica knits has 18 squares on Monday .She knits 7 more squares each day from Tuesday through Thursday .How many squares did Eric
pantera1 [17]

Answer:

39 squares in all

Step-by-step explanation:

step 1 right it out

18-monday

7-tuesday

7-wednesday

7-thursday

Step 2 add them all up

then you get 39

hopes it help make me brainlist

3 0
2 years ago
A researcher computes the following 2 x 3 between-subjects ANOVA, in which 11 participants were observed in each group. Which ef
pishuonlain [190]

Answer:

D. There were no significant effects.

Step-by-step explanation:

The table below shows the representation of the significance level using the two-way between subjects ANOVA.

Source of Variation            SS          df          MS          F                P-value

Factor A                             10          1              10           0.21           0.660

Factor B                             50         2             25          0.52          0.6235  

     

A × B                                  40          2             20         0.42           0.6783

Error                                   240        5             48           -               -

Total                                   340       10             -             -                  -

From the table above , the SS(B) is determined as follows:

SS(B) = SS(Total)-SS(Error-(A×B)-A)

         =  340-(240-40-10)

         = 50

A researcher computes the following 2 x 3 between-subjects ANOVA;

k=2

n=3

N(total) = no of participants observed in each group =11

df for Factor A= (k-1)

=(2-1)

=1

df for Factor B = (n-1)

=(3-1)

=2

df for A × B    

 = 2 × 1

 = 2

df  factor for total

=(N-1)

=11-1

=10

MS = SS/df

Thus, from the table, the P-Value for all data is greater than 0.05, therefore we fail to reject H₀.

4 0
2 years ago
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