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faltersainse [42]
3 years ago
7

The sequence below follows the Fibonacci rule.

Mathematics
1 answer:
insens350 [35]3 years ago
5 0

Answer:

89

Step-by-step explanation:

8, 13,

8+13= 21

13+21 =34

21+34=55

34+55=89

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Which is bigger 4/6 or .77
jok3333 [9.3K]
First, let's convert 0.77 to a fraction. 

\frac{0.77}{1}

Multiply by 100

\frac{77}{100}

Now make the denominators the same, to make it easier to find which fraction is greater. We can do this by finding the LCM of the denominators, then however many times the denominator goes into that number, we multiply the numerator by the same amount.

For example, the LCM of 100 and 6, is 300. 6 goes into 300 50 times, so the numerator for 4/6 is 200 (4 x 50 = 200). :)

\frac{200}{300} \ \textless \  \frac{231}{300}

The answer is 0.77 is greater than 4/6. :)

Hopefully this helps! If you have any more questions or don't understand, feel free to DM me, and I'll get back to you ASAP! :)
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4 years ago
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Please help me!! I don’t understand!!!
Dovator [93]

Answer:

Ask your John Brown teacher!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Step-by-step explanation:

7 0
3 years ago
Find the product.<br><br> -7(-a^2)(-b^3)
Reil [10]
I belive the answer to your question would be -7a^2b^3

4 0
4 years ago
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You invest in a new technology company. The cost includes an overhead of $30,000, p production costs of $2500 per item produced.
Artyom0805 [142]

Answer:

A. C(x) = 30.000 + 2500x

B. R(x) = 3125x

C. 48 items break even point

Step-by-step explanation:

A. The cost function C(x) is fixed cost plus variable cost.

In this case overhead works as fixed cost, we can write:

C(x) = 30.000 + 2500x

B. Revenue R(x) would be the price multiplied by quantity of items (x).

R(x) = 3125x

C. Break even point

To get the break even point we set R(x) = C(x) and find the value of x.

R(x) = C(x)

3125x = 30.000 + 2500x

3125x-2500x=30.000

625x=30.000

x=30.000/625

x=48

It means when you sell 48 items the costs will even revenue. So if you sell more than 48, then it's going to be profitable. If you sell less than 48, you will be losing money.

5 0
4 years ago
Is 1/sec^2(θ) the same as cos^2(θ)
dexar [7]
\frac{1}{sec^2\theta}=cos^2\theta\\\\L=\frac{1}{\left(\frac{1}{cos\theta}\right)^2}=\frac{1}{\frac{1}{cos^2\theta}}=1:\frac{1}{cos^2\theta}=1\cdot\frac{cos^2\theta}{1}=cos^2\theta=R
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3 years ago
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