$\displaystyle\frac{n^2-10n+24}{n^2-13n+42}-\frac{9}{n-7}=\frac{(n-6)(n-4)}{(n-6)(n-7)}-\frac{9}{n-7}\\\\=\frac{n-4}{n-7}-\frac{9}{n-7}=\frac{n-4-9}{n-7}\\\\=\frac{n-13}{n-7}$

The last choice is appropriate.

3 0

3 years ago

Which expression does not factor? m3 + 1 m3 – 1 m2 + 1 m2 – 1

Luda [366]

Answer:

$m^2 +1$

Explanation:

All the other expressions can be factorized. Let's see why:

1) $m^3 +1$

This is the sum of the cubes, and this can be factorized as follows:

$a^3+b^3=(a+b)(a^2-ab+b^2)$

In this case, a=m and b=1, so we can factorize as

$m^3+1=(m+1)(m^2-m+1)$

2) $m^3-1$

This is the difference between two cubes, and this can be factorized as follows:

$a^3-b^3=(a-b)(a^2+ab+b^2)$

In this case, a=m and b=1, so we can factorize as

$m^3-1=(m-1)(m^2+m+1)$

3) $m^2-1$

This is the difference between two square numbers, and it can be factorized as follows

$(a^2-b^2)=(a+b)(a-b)$

In this case, a=m and b=1, so we can factorize as

$m^2-1=(m+1)(m-1)$

4 0

3 years ago

Read 2 more answers

Farouc Jaffer.

harkovskaia [24]

Answer:

1996.66.......

Step-by-step explanation:

6 0

3 years ago