<span>Actually the developing offspring in the eight week of pregnancy is medically know as a fetus,Where the lungs of the baby are nearly developed, and baby continues to grow and mature, then reflexes of work starts woking slowly, after which baby prepares itself for delivery in next few days.</span>
Answer:
Supreme Court (top)
Courts of Appeal (middle)
District Courts (bottom)
Explanation:
Answer:
1. Fluorine (7 electrons) => c. steals 1 electron
2. Calcium (2 electrons) => a. gives away 2 electrons
3. Oxygen (6 electrons) => d. steals 2 electrons
4. Lithium (1 electron) => e. gives away 1 electron
5. Xenon (8 electrons) => b. neither gives away nor steals any electron
Explanation:
Given the following valence electrons of the atoms listed above, each atom can be matched to its corresponding number of electrons it can steal or give away as they form bonds and attain a stable state:
1. Fluorine (7 electrons) => this will steal 1 electron from another atom to attain a stable state when it comes to make the number of electrons 8.
2. Calcium with 2 valence electrons, will give away this 2 electrons in its outer shell to be stable and form bond with another atom that will accept these 2 electrons.
3. Oxygen with 2 valence electrons, will steal 2 electrons to make the electrons in its outer shell 8, as it bonds with another atom to become stable.
4. Lithium will give away 1 electron to become stable when it combines.
5. Xenon with 8 electrons in its outer shell is in a stable state and kind of inert. It doesn't need to receive or steal any electron from or to any other atom in this state.
Answer:
Explanation:
The Genotype of the woman is XCbXN
The man XNY
Since the allele for the color blindness is carried on one of the X -chromosomes of the carrier mother, then the male children will be color blind or carrier deopending on the defective gene they inherited. Since they will receive the defective or normal allele from the mothers,but the female will carriers or normal because they will inherit either defective allele or normal allele from the mother,but normal X allele from the father.
Assuming the colorbind gene was inherited by One of the boys, and the girls take the defective genes
1. XNY vs XCbXN.Then the one of the boys will be colorblind and the one of girls will be carriers. XNXCb, XNXN, XCbY,XNY 50 %
2.If the two boys take the effective genes from the mothers. and none of the girls take the defective alelle
Then the two boys will be colorblind and the girls will be carrries XcbY,XcbY and XNXN XNXN.(normal girls).
The proportions that will be the females since the girls can only take the defective allele from one of the normal and defective allele from the mother. Assuming the girls take the defective allele from the mothers and take normal from the father,they will all be carriers,since the X of the father is normal.
They can not have a color blind girl.Since the father is normal It takes two colorblind X-chromosome to give a girl.
Prophase-->Metaphase-->Anaphase-->Telophase
