Answer:
Mailing preparation takes 38.29 min max time to prepare the mails.
Step-by-step explanation:
Given:
Mean:35 min
standard deviation:2 min
and 95% confidence interval.
To Find:
In normal distribution mailing preparation time taken less than.
i.eP(t<x)=?
Solution:
Here t -time and x -required time
mean time 35 min
5 % will not have true mean value . with 95 % confidence.
Question is asked as ,preparation takes less than time means what is max time that preparation will take to prepare mails.
No mail take more time than that time .
by Z-score or by confidence interval is
Z=(X-mean)/standard deviation.
Z=1.96 at 95 % confidence interval.
1.96=(X-35)/2
3.92=(x-35)
X=38.29 min
or
Confidence interval =35±Z*standard deviation
=35±1.96*2
=35±3.92
=38.29 or 31.71 min
But we require the max time i.e 38.29 min
And by observation we can also conclude the max time from options as 38.29 min.
Answer:
x <-3
Step-by-step explanation:
15 <-5x
divide both sides by 5 but since the coefficient of x is negative after dividing the sign changes.
x <-3
First we can subtract the sales tax so we are just working with what's left: $17 - $0.92 = $16.08. Then we multiply the price of the sandwiches by 2 for the number Corey bought: 5.25 x 2 = $10.50. Then subtract that amount from what you have left: $16.08 - 10.50 = 5.58. Then, take that amount and divide it by three drinks: $5.58 / 3(drinks) = $1.86 per drink. I don't see the table so I hope this answers the question well enough!:)
"ug" stands for microgram. You can convert microgram into grams by multiplying a certain factor. For this case, 1 microgram is known to be 1x10^-6 g. This is the conversion factor that will be multiplied to 3.54.
3.54 ug ( 1x10^-6 g / 1 ug ) = 3.54 <span>x10^-6 g</span>
