the third one is incorrect
X^N - X^12 = X^2
N=14
It isn't at all!
When dividing numbers, the easiest way is to imagine the values as a fraction, and then reduce that fraction. If it reduces to a core fraction (ones that you should know their decimal value without thinking), then you have your answer.

We simplified our fraction by dividing the numerator and denominator by 4, which left us with

, which we know is equal to
0.8.
You may be confused thinking that 0.8 is the same as 8. 0.8 is actually a tenth of the value of 8. This makes them very different values.
Below, I have also included a picture to help you memorize your common/core fractions. I recommend learning these as they will help you get through all sorts of math, from Geometry to Calculus!
This is distance formula is sqr. root of (x1-x2)^2 + (y1-y2)^2
(3-(-4))^2+ (-94-(-195))
7^2 101^2
49+ 10,201
square root of 10250
101.242 or the closest answer to this
Answer:
D) the standard error for her sample is 15
Step-by-step explanation:
Samantha is 95% certain that between 50% and 70% of the first year students agree that they should be able to bring a car to campus.
Here
- 95% is the confidence level.
- The range between 50% and 70% indicates 95% confidence interval.
- 60% is the average proportion of the first year students at her university think they should be able to bring a car to campus.
- 10% (0.1) is the margin of error from the mean
Since standard error can be obtained by dividing margin of error by the z-statistic of the confidence level which is 1.96. The standard error for her sample
does not equal to 15.
Answer:
Answer is in the explanation
Step-by-step explanation:
I don't know exactly word from word what your choices look like...
but I can describe per each box what happened in my own words:
First box: They multiply first equation by 3 and the second equation by 2 to obtain the equations in that first box.
Second box: They subtracted the two equations in the first box to obtain 1x+0y=2 which means 1x=2 or x=2 (this is called solving a system by elimination
Third box: They used their first original equation (before the multiplication manipulation) and plug in the value they got for x which was 2 giving them 3(2)-2y=10
Fourth box: They simplified the equation 3(2)-2y=10 by performing the multiplication 3(2) giving them 6-2y=10
Fifth box: They subtracted 6 on both sides giving them -2y=4
Sixth box: They divided both sides by -2 giving them y=-2
I will summarize then what I wrote above:
1st box: Multiplication Property of Equality
2nd box: Elimination
3rd box: Substitution (plug in)
4th box: Simplifying
5th box: Subtraction Property of Equality
6th box: Division Property of Equality