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Rom4ik [11]
2 years ago
12

Solve the literal equation for x. y=5x-rx-5

Mathematics
1 answer:
Alchen [17]2 years ago
7 0

Answer:

x = \frac{y+5}{(5-r)}

Step-by-step explanation:

Given the literal equation, y = 5x - rx - 5,

In order to solve for x, start by adding 5 on both sides of the equation:

y + 5 = 5x - rx - 5 + 5

y + 5 = 5x - rx

Next, factor out x from the right-hand side of the equation:

y + 5 = x(5 - r)

Finally, divide both sides by (5 - r) to isolate x:

\frac{y+5}{(5-r)} =  \frac{x(5 - r)}{(5-r)}

\frac{y+5}{(5-r)} =  x

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Please Help! My question is in the picture.
Varvara68 [4.7K]
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Second, determine the ratio of the progression
r = a₂/a₁
r = a₂ ÷ a₁
r = 1/2 ÷ 2
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Fourth, determine a₁. a₁ is the first term of the progression
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Final answer:
Recursive rule
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3 years ago
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Step-by-step explanation:

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