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Dennis_Churaev [7]
3 years ago
8

Need this picture solved I don't know

Mathematics
1 answer:
Alika [10]3 years ago
8 0

What item do you want the most? Once you tell me this I can write your whole essay.


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Help pleasee someone?
stira [4]

Answer:

Step-by-step explain

4 0
3 years ago
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Solve. (x + 3)^1/2– 1 = x
Natali [406]

Answer:

x=1

Step-by-step explanation:

(x + 3) ^{ \frac{1}{2} }  - 1 = x  \\  \sqrt{x  + 3}   - 1 = x \\  \sqrt{x + 3}  = x + 1 \\ square \: both \: sides \\ x + 3 =  {x}^{2}  + 2x + 1 \\  {x}^{2}  + 2x - x + 1 - 3 = 0  \\  {x}^{2}  + x - 2 = 0  \\ x ^{2}  + 2x - x - 2 = 0  \\ (x^{2}  + 2x) - (x  + 2) = 0 \\ x(x + 2) - 1( x + 2) = 0 \\ (x - 1)(x + 2) = 0 \\ x - 1 = 0 \\ x = 1 \\  \\  \\ x  +  2 = 0 \\ x =  - 2

8 0
3 years ago
William has 24 24 cans of fruit and 60 60 cans of vegetables that he will be putting into bags for a food drive. He wants each b
Snezhnost [94]

Answer:

William will make 12 bags of food and each of the bag will contains 2 cans of fruit and 5 cans of vegetables.

Step-by-step explanation:

Given:

Number of fruits cans = 24

Number of veggies cans = 60

William will have to distribute them in equal bags with equal cans of fruits and vegetables respectively.

For this:

We have to find the GCF (greatest common factor) of 24 and 60.

GCF by listing out the factors method.

Factors of 24  : 1,2,3,4,6,8,12,24

Factors of 60 : 1,2,3,4,5,6,10,12,15,20,30,60

So,

The greatest common factor of 24 and 60 is 12.

The number of bags William will used for equal distribution = 12

Now,

We have to distribute the veggies and fruits in equal number of cans to these 12bags.

Number of fruits cans used in each bag = \frac{24}{12} = 2

Number of vegetables can used in each bag = \frac{60}{12} =5

We can say that:

William will make 12 bags of food and each of the bag will contains 2 cans of fruit and 5 cans of vegetables.

4 0
3 years ago
A system of linear equations with fewer equations than unknowns is sometimes called an underdetermined system. Can such a system
elena55 [62]

Answer:

No, it cannot have a unique solution. Because there are more variables than​ equations, there must be at least one free variable. If the linear system is consistent and there is at least one free​ variable, the solution set contains infinitely many solutions. If the linear system is​ inconsistent, there is no solution.

Step-by-step explanation:

the questionnaire options are incomplete, however the given option is correct

We mark this option as correct because in a linear system of equations there can be more than one solution, since the components of the equations, that is, the variables are multiple, leaving free variables which generates more alternative solutions, however when there is no consistency there will be no solution

3 0
3 years ago
Copy the problem, mark the givens in the diagram. Given: CS ≅ HR, ∠CHS ≅ ∠HCR, ∠CSH ≅ ∠HRC, Prove: CR ≅ HS
Veseljchak [2.6K]

Explanation:

1. CS ≅ HR, ∠CHS ≅ ∠HCR, ∠CSH ≅ ∠HRC — given

2. ∆CRH ~ ∆HSC — AA similarity theorem

3. ∠SCH ≅ ∠RHC — corresponding angles of similar triangles are congruent

4. CH ≅ HC — reflexive property of congruence

5. ∆CRH ≅ ∆HSC — SAS congruence theorem

6. CR ≅ HS — CPCTC

6 0
4 years ago
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