Answer:
A.+4
Step-by-step explanation:
Graph pass (1 , 0) and (4 , 0)
y = (x - 1) (x - 4) = x² - 5x + 4
c = 4
We know that the sandbox is square, and that the area is 160 sq ft. Since A = s^2 for a square, let's work backwards and find s if A = 160 sq ft = s^2.
s^2 = 160 = 16(10). We do this because 16 is the largest perfect square factor of 160.
Then the length of one side of the square is approx. s = 4√10 ft (12.65 ft)
First of all, expand the left hand side:

Sum like terms:

Add 3 to both sides:

Subtract 3x from both sides:

So this is the solution. Every number smaller than 8 (excluded) is part of the solution of this inequality.
Answer:
Both the relations are functions, the correct answer is a.
Step-by-step explanation:
In order to solve this problem we will first find the inverse relation as shown below:

Functions are relations between two groups of numbers, for which the input must generate only one output. Using this definition we can classify both the relation and its inverse as a function, therefore the correct answer is a.